Three forces are acting on the bracket ABC as shown in Fig 2. Calculate the wrench resultant of the three forces and the y- and z- coordinates of the point through which this resultant passes the y-z plane.
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- Find the internal force systems acting on sections 1 and 2.Using the Cartesian components (rectangular components), determine the resultant of the force vectors answering the magnitude in the space provided below and the direction in the procedure document. Only handwritten Draw to approximate scale the sum-of-forces polygon showing the original vectors and the resultant. In a separate document show the entire work. F = 252lbs, F₂ = 130lbs, a = 65° F3 = 55lbs, m = 6.2, and n = 8.6Q2-4- Use the graphical method to find the magnitude and direction of the resultant of these forces F-500 N 700 N
- Determine the magnitude and direction of the resultant of the following forces: 50 N at 50 degrees,60 N at 120 degrees,40 N at 220 degrees,30 N at 330 degrees. All angles are measure from the positive x-axis. Use the component method. Select one: a. 75 N: 42º b. 50 N: 87º c. 54 N: 87º d. 101 N: 89ºQ4b. Force vectors F1 and F2 act on body Pwith the resultant force vector R. The resultant force R= 575 N and the angle between Rand the x-axis is of 320. If F1 = 275 N and the angle between F1 and the x-axis is 560, determine the angle between F2 and the x-axis. *Assume coplanar vector forces and give your answer in degrees to two decimal places. Body, P Answer: y F1 R F2The following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method. Show solution, formula and the FBD and pls write legible
- Consider a resultant force of 50N along the negative y-axis. The resultant was calculated as a sum of the following four tensile force: F1= 100N at 70, F2= 300N at 190 and F3 = 150N at 340 and F4 . Find the magnitude and the direction of the force F4. Find the force F4. Use the counter clockwise direction as the positive direction of the angle from the positive x-axis . Provide the answer to 2 decimal places.The following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method. Pls show the solution, formula and free body diagram.Find the y-component a force, 100N, acting 45 degrees to the right of the negative y-axis.
- Determine the magnitude and direction of the resultant of the concurrent forces described below. Draw the necessary figure. F1= 300 lb, up to the right, 45 degree with respect to positive x-axis F2= 400 lb, up to the left, 60 degree with respect to x-axis F3= 200 lb, down to the left, 30 degree with respect to x-axis3. Four forces act on a point but only three of them are shown in the figure below. Determine the magnitude and direction of the fourth (missing) force if the magnitude and direction of the four forces is 95.0 lb and points in the first quadrant at an angle of 40° above the x-axis. (Hint: all 4 vectors should be drawn in your FBD.) 70 lb 60° * 60⁰ 50° 50 lb 120 lb/ 8Q2:- For the block shown in the figure below, the 40 lb. force is passing through points EF, the 50 Ib. force is passing throuch points JB, and the force 20 lb. is passing through point C. 1. Find the resultant force and its directions. 2. Determie the resultant moment of three forces in Figure about the x-axis, the y-axis, and the z-axis. 20 ib 50 lb 40 lb 3 dimensions in inch