The vector function r(t) = (1+2 cost) i+3j+(5 – 2 sin t) k | traces out a circle in 3-space as t varies. De- termine the radius and center of this circle.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.2: Graphs Of Equations
Problem 40E
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1. radius = 2, center
(3, 1, 5)
2. radius = 1, center
(3, 1, –5)
3. radius = 2, center =
(5, 1, 3)
4. radius = 1, center
(3, 1, 5)
5. radius
2, center =
(1, 3, 5)
6. radius = 1, center
(-5, 1, 5)
Transcribed Image Text:1. radius = 2, center (3, 1, 5) 2. radius = 1, center (3, 1, –5) 3. radius = 2, center = (5, 1, 3) 4. radius = 1, center (3, 1, 5) 5. radius 2, center = (1, 3, 5) 6. radius = 1, center (-5, 1, 5)
The vector function
r(t)
(1+2 cos t) i+ 3j+(5 – 2 sin t) k
traces out a circle in 3-space as t varies. De-
termine the radius and center of this circle.
Transcribed Image Text:The vector function r(t) (1+2 cos t) i+ 3j+(5 – 2 sin t) k traces out a circle in 3-space as t varies. De- termine the radius and center of this circle.
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