The spring has a stiffness k = 200 N/m and is unstretched when the 25-kg block is at 4. Determine the acceleration of the block when s = 0.4 m. The contact surface between the block and the plane is smooth.
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- The spring has a stiffness of k = 800 N/m and an unstretched length of 200 mm. Determine the force in cables BC and BD when the spring is held in the position shown. A k = 800 N/m -500 mm 400 mm- 400 mm 300 mmEach spring has an unstretched length of 2 in and a stiffness of fc = 330 N/m . 1. Determine the stretch in 04 spring required to hold the 18-kg crate in the equilibrium position shown. 2. Determine the stretch in OB spring required to hold the 18-kg crate in the equilibrium position shown.Determine the stretch in each spring for for equilibrium of the 1.8-kg block. The springs are shown in the equilibrium position. (Figure 1) No elements selected 3m 4 m 3 m kAC = 20 N/m igure kan = 30 N/m www 1 of 1 3 m 4 m kAD- 40 N/m 3 m kAc = 20 N/m kAn- 30 N/m www kAD- 40 N/m Select the elements from the list and add them to the canvas setting the appropriate attributes.
- Q4 / Determine the unstretched length (Lo) of spring Ac if a force P= 400 N causes the Ø=60° for equilibrium cord AB is 0.6m long . Take K=850 N/m. As shown in fig (4)? 0.6 m 0.6 m wwwThe 10 Ib weight is supported by the cord AC, a roller and by a spring. If the spring has an unstretched length of 8 in. and the weight is in equilibrium when d = 4 in., determine the stiffness k of the spring. 12 in. В Select one: O a. k = 7.8 Ib/in b. k = 6.8 lb/in O c. k = 5.8 Ib/in O d. k = 4.8 Ib/inDetermine the spring stiffness K in N/m to maintain equilibrium of the scissors linkage. The linkage is subjected to a force of P = 800 N. The spring is un-stretched when initial angle θ0 = 10º. Neglect the mass of the links. Determine the spring stiffness k in N/m for equilibrium when θ = 65º.
- The homogeneous box has mass m. The magnitude of force P is slowly increased until motion occurs. Motion could occur as slipping or tipping and you must decide which occurs first. Find the value of P which first causes motion. A B Answer: P = 32° P 1.5 d C mg μs = 0.43A.The bar of negligible weight is supported by two springs, each having a stiffness k = 98 N/m. If the springs are originally unstretched, and the force is vertical as shown, determine the angle the bar makes with the horizontal, when the 31-N force is applied to the bar. B.Determine the stiffness k of each spring so that the 32-N force causes the bar to tip = 13.6° when the force is applied. Originally the bar is horizontal and the springs are unstretched. Neglect the weight of the bar.1. Determine the stretch in each of the two springs required to hold the 20-kg crate in the equilibrium position shown. Each spring has an unstretched length of 2 m and a stiffness of k = 300 N/m. 4m 12 m 6 m
- Determine the required length of cord AC , so that the 8-kg lamp can be suspended position shown. The undeformed length of spring AB is 0.4m and the 3 m in the kAB= 320 N/m 30° spring has a stiffness of kAB = 300 N/m. ہ إضافة ملفThe 30 kg block is supported by two springs having the stiffness shown. Determine the stretch of spring AC, S(AC): 0.4 m 0.3 m. 0.4 kac- 1.5 kN/m 1.2 KN/m Select one: а. S(AC) = 0.17 m b. S(AC) = 0.5 m c. S(AC) = 0.22 m d. S(AC) = 0.1189 m3-18. If the spring DB has an unstretched length of 2 m, determine the stiffness of the spring to hold the 40-kg crate in the position shown. 3-19. Determine the unstretched length of DB to hold the 40-kg crate in the position shown. Take k = 180 N/m. %3D -2 m- 3 m В 2 m www A