The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? A

The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? A

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter4: Newton's Laws Of Motion

Section: Chapter Questions

Problem 91AP: The board sandwiched between two other boards in Figure P4.91 weighs 95.5 N. If the coefficient of...

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The board sandwiched between two other boards in Figure P4.91 weighs 95.5 N. If the coefficient of friction between the boards is 0.663, what must be the magnitude of the compression forces (assumed to be horizontal) acting on both sides of the center board to keep it from slipping? Figure P4.91
1. The man is supporting his weight with friction. He's pressing into the rock walls with his feet and back. Suppose friction is supporting all his weight - he's perhaps steadying himself with the rope but not pulling up. The normal force on his feet (both feet together) and back are the same, 743.2 N. The coefficient of static friction is 0.54. If he's just barely not slipping down, what must be his mass? 40.95 Previous submissions: 40.95 kg kg incorrect
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