The combustion of gasoline (octane) in a car engine can be represented by the following equation: 2C3H18(1) + 2502(g) ---> 16CO2(g) +18H2O(g) a. What mass of oxygen is used up to burn a full tank of 36.00 kg of gasoline? b. Why might a vehicle that is calibrated to run perfectly at sea level run poorly at higher elevations?
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- 3.1524 g HCI (FW 36.46) was diluted with 45 mL water and titrated with 1.0149 M NAOH (FW 40) using methyl red as indicator. 28.02 mL of NAOH was required to neutralize the HCI. Calculate the percentage w/w of HC. Record your answer in decimal notation to 2 decimal places. Answer = % w/w %3DConsider the calcination of CaCO3: CaCO3 -> CaQ + CO, Before calcination, the initial weight of CaCO3 is 2.5g. After calcination, the final weight of CaCO3 was measured at 2.0 g. Calculate the conversion of CaCO; particles (x) using the following equation: m CaCO, -m CaCo, ) x = m Caco, -MCao |A first-stage recovery of magnesium from seawater is precipitationof Mg1OH22 with CaO:Mg2+(aq) + CaO(s) + H2O(l)---->Mg(OH)2(s) + Ca2+(aq) What mass of CaO, in grams, is needed to precipitate 1000lb of Mg(OH)2?
- 5R) The net ionic equation for formation of an aqueous solution of Nil2 accompanied by evolution of CO2 gas via mixing solid NICO3 and aqueous hydriodic acid is A) 2NICO3 (s) + HI (aq) - 2H20 (1) + CO2 (g) + 2N12+ (aq) 2H20 (1) + CO2 (g) + Ni2+ (aq) + HI (aq) B) NICO3 (s) + I (aq) O NICO3 (s) + 2H* (aq) H20 (1) + CO2 (g) + Ni2+ (aq) 2H20 (1) + CO2 (g) + Nil2 (aq) D) NICO3 (s) + 2HI (aq) E) NICO3 (s) + 2HI (aq) H20 (1) + CO2 (g) + Ni2+ (aq) + 21- (aq) Answer. CUnit 7A: RA--Chemical Reactions and Stoichiometry 15/20 answered Close Homework . Due in 4 hours Molten iron and carbon dioxide gas are products in the industrial iron making process which passes carbon monoxide through molten iron ore, Fe203, at 1500°C. Write a balanced chemical equation for the production of iron. Chem 7 8 9 H 4 6 1 2 3 mol y g mol-1 DI + || SHOWSodium carbonate is a reagent that may be used to standardize acids in the same way that you have used KHP in this experiment. In such a standardization it was found that a 0.498-g sample of sodium carbonate required 24.8 mLmL mL of a sulfuric acid solution to reach the end point for the reaction. Na2CO3(aq)+H2SO4(aq)→H2O(l)+CO2(g)+Na2SO4(aq)Na2CO3(aq)+H2SO4(aq)→H2O(l)+CO2(g)+Na2SO4(aq) What is the molarity of the H2SO4H2SO4?
- 3. (a) If 10.0 mL of H2SO4 (sp. Gr. 1.50, containing 48.7% of combined SO3 by weight) is diluted to 400 mL, what is the normality of the solution as an acid? (b) What volume of 6.00 M H2SO4 should be added to this in order to make the resulting mixture 1.00 N as an acid? FW's : H2SO4 = 98; SO3 = 80(a) How many grams of nickel are contained in 10.0 g of a 10.2 wt% solution of nickel sulfate hexahydrate, NiSO4 ? 6H2O (FM 262.85)? (b) The concentration of this solution is 0.412 M. Find its density.Lead hydroxide, Pb(0H)2(s) | Pb(0H)2(s)Pb+2(aq)+20H-(aq) | Ksp=1.4x10-20 H2O(aq)H*(aq)+OH-(aq) Pb(OH)2 Water Kw=1.00x10-14 Molar masses 241.21 Pb 207.20 OH- 17.01 If Pb+2(aq) is controlled by the solubility of Pb(OH)2, what Pb+2(aq) concentration is expected if pH=p0H=7.00? b. What pH would be required to lower Pb+2(aq) to 2.07 ppb? a.
- Bb Blackboard Collaborate Ultra – 1 X Bb Collaborate - Live Tutorial Ses X O Mail - Jenna Lewis - Outlook G 0.615 ml to litres - Google Search x + 8 https://au.bbcollab.com/collab/ui/session/playback Not syncing O Instagram (11) Facebook In class questions: Q97: - Use the provided equation to calculate the following: KMNO, (aq) + HCI (aq) → MnCl, (aq) + Cl, (g) + H,0 (1) + KCI (aq) а. The moles of H,0 that can be obtained from 15.0 ml of 0.250 M HCI. b. The volume of 0.150 M KMno, needed to produce 0.0143 g MnCl,. С. The volume of 2.50 M HCI needed to produce 125 ml of 0.525 M KCI. 2KMNO, (aq) + 16HCI (aq) → 2MNCI, (aq) + 5Cl, (g) + 8H,0 (1) + 2KCI (aq) 01:36:12 01:59:28 [CC 9:14 AM O Type here to search 14°C Sunny 4) ENG 9/09/2021VIII. A primary standard of HCI is sodium carbonate, Na2CO3. A measured mass of solid Na2CO3, mNa2CO3' in grams, is dissolved in water and then titrated with HCI solution using methyl 2 NaCl + CO2 + H2O. orange indicator. The reaction is: Na2CO3 + 2 HCI- Complete the following formulas using the context described above: MHCI × VHCI in mL at the methyl orange endpoint = mNa2CO3 × ( )= mol of Na2CO3 mol of Na2CO3 X (— ( - - )= mol of HCl10:44 PM Sat Apr 13 < STARTING AMOUNT Question 8 of 14 Determine the mass in grams of HCI that can react with 0.750 g of Al(OH), according to the following reaction Al(OH),(s) + 3 HCl(aq) AICI,(aq) + 3 H,O(aq) Tap here or pull up for additional resources ADD FACTOR * ( ) ANSWER RESET C 6.022 x 1023 36.46 18.02 0.351 2.25 0.750 78.00 0.0288 0.117 1 1.05 9.60 x 10 3 133.33 g AICI mol AICI, g Al(OH)3 mol HCI mol Al(OH), g HCI g H₂O mol H₂O 31% Submit