The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.76° F. What temperature represents the 95th percentile? Click to view page 1 of the table. Click to view page 2 of the table. O A. 99.57° F O B. 100.09° F OC. 97.35° F OD. 99.85° F

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
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ISBN:9780547587776
Author:HOLT MCDOUGAL
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Chapter11: Data Analysis And Probability
Section: Chapter Questions
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The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.76° F. What temperature represents the 95th percentile?
Click to view page 1 of the table. Click to view page 2 of the table.
A. 99.57° F
O B. 100.09° F
OC. 97.35° F
O D. 99.85° F
Click to select your answer.
(?
P Type here to search
%23
Transcribed Image Text:The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.76° F. What temperature represents the 95th percentile? Click to view page 1 of the table. Click to view page 2 of the table. A. 99.57° F O B. 100.09° F OC. 97.35° F O D. 99.85° F Click to select your answer. (? P Type here to search %23
2 of 10 (0 complete
Use a standard normal table to find the z-score that corresponds to the 30" percentile.
Click to view page 1 of the table. Click to view page 2 of the table.
А. 0.84
В. 1.88
O C. -2.75
D. -0.525
Click to select your answer.
Type here to search
Transcribed Image Text:2 of 10 (0 complete Use a standard normal table to find the z-score that corresponds to the 30" percentile. Click to view page 1 of the table. Click to view page 2 of the table. А. 0.84 В. 1.88 O C. -2.75 D. -0.525 Click to select your answer. Type here to search
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Given:

μ=98.6σ=0.76

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