The angular position of a point on the rim of a rotating wheel is given by 0 = 9.12t-5.20t² +2.91t3, where is in radians and t is in seconds. What are the angular velocities at (a) t = 2.71 s and (b) t = 9.95 s? (c) What is the average angular acceleration for the time interval that begins at t = 2.71 s and ends at t = 9.95 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval? (a) Number (b) Number i (c) Number i (d) Number i (e) Number i Units Units Units Units Units

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Motion In Two Dimensions
Section: Chapter Questions
Problem 30P: A point on a rotating turntable 20.0 cm from the center accelerates from rest to a final speed of...
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The tolerance is -+1 in the 3rd significant digit 

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The angular position of a point on the rim of a rotating wheel is given by 0 = 9.12t -5.20t² + 2.91t³, where is in radians and t is in
seconds. What are the angular velocities at (a) t = 2.71 s and (b) t = 9.95 s? (c) What is the average angular acceleration for the time
interval that begins at t = 2.71 s and ends at t = 9.95 s? What are the instantaneous angular accelerations at (d) the beginning and (e)
the end of this time interval?
(a) Number
(b) Number i
(c) Number i
(d) Number i
(e) Number
i
Units
Units
Units
Units
Units
Transcribed Image Text:The angular position of a point on the rim of a rotating wheel is given by 0 = 9.12t -5.20t² + 2.91t³, where is in radians and t is in seconds. What are the angular velocities at (a) t = 2.71 s and (b) t = 9.95 s? (c) What is the average angular acceleration for the time interval that begins at t = 2.71 s and ends at t = 9.95 s? What are the instantaneous angular accelerations at (d) the beginning and (e) the end of this time interval? (a) Number (b) Number i (c) Number i (d) Number i (e) Number i Units Units Units Units Units
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