The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.40 rad/s)t + p]. If at t = 0, 0 = 0.0200 rad and de/dt = -0.160 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.)

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Chapter 15, Problem 049 GO
The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.40 rad/s)t + p]. If at t = 0, 0 = 0.0200 rad and de/dt = -0.160 rad/s, what are (a)
the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.)
Pivor
point
L.
Is= Le
F,cose
Fgsine-
(a)
(6)
(a) Number
Unit
(b) Number the tolerance is +/-2%
Unit
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Transcribed Image Text:Chapter 15, Problem 049 GO The angle (with respect to the vertical) of a simple pendulum is given by e = 0mcos[(4.40 rad/s)t + p]. If at t = 0, 0 = 0.0200 rad and de/dt = -0.160 rad/s, what are (a) the phase constant p and (b) the maximum angle 0m? (Hint: Don't confuse the rate de/dt at which e changes with the w of the SHM.) Pivor point L. Is= Le F,cose Fgsine- (a) (6) (a) Number Unit (b) Number the tolerance is +/-2% Unit Click if you would like to Show Work for this question: Open Show Work
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