Solve for the unknown quantity for the following solutions. 13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of 1.75 M? 14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL of water? 15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate in water? 16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate solution to 1.0 L? mol amount arity. tion 1. Ca ulate the
Solve for the unknown quantity for the following solutions. 13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of 1.75 M? 14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL of water? 15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate in water? 16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate solution to 1.0 L? mol amount arity. tion 1. Ca ulate the
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.8E
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Set up for Solving 13-16?
Transcribed Image Text:Solve for the unknown quantity for the following solutions.
13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of
1.75 M?
14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL
of water?
15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate
in water?
16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate
solution to 1.0 L?
M =
1. Calculate the Molarity/concentration
given amount solute and volume solute
2. Molarity is given
mol-amount
volume
use as a conversion factor
3. Dilution calculations
M₁ V₁ = M₂V₂
sig figs
plug back in to see if Correct
L
IL
XM → * mal OR
IL
x mal
Conversions from there
mar
M CUCI 2 V
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