Question 20 Listen . You do some further dragon genetic research and find the following Fire breathing (Fb) and the ability to fly (FI) are 20 map units apart Fire breathing and Green eyes (G) are 3 map units apart The ability to fly and long tail (T) are 7 map units apart Green eyes and long tail are 10 map units apart recessive alleles fb cannot breath fire g blue eyes f can not fly t short tail Based on this information, the correct map order is a) Fb T G FI b) FI G T Fb c) Fb FI GT d) Fb G T FI
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Genetics Question 20
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- Question 4. Recalling the eye pigment pathway in Drosophila, match the following fly genotypes with the appropriate phenotypes (w=white, bw-brown, cn=cinnabar red, st=scarlet red, se=sepia brown) a. b. d. W W W W ; ; ; ; bw + bw + + cn bw + Genotype A + cn bw cn bw cn Genotype B Genotype C + cn Genotype D ; ; ; ; st+ st se st se + se st se + se st se + se Scarlet Sepia Sepia White < < <AnalyzingHair Length Analyzing Hair Color Two genetic crosses have been proposed between male and female mice with varying hair length. These traits are described in the table below. For each genetic cross, complete the sentence that describes the predicted outcome of the cross. Use a separate sheet of paper to construct a Punnett square for each cross to accurately make your predictions. Allele Dominant or recessive? Trait description B dominant short hair recessive long hair 1. Baby mice produced from the cross between male BB and female bb parents will include Choose genotypes and Choose - phenotypes. 2. Baby mice produced from the cross between male Bb and female Bb parents will include Choose genotypes and Choose - phenotypes. javascript void(0), DELL SCNow cross two of the F₁ offspring. Parent 1 Gametes F2 Offspring Parent 2 Gametes 24. What is the phenotypic ratio in the F2 generation? 25. In the dihybrid cross you have considered two traits at a time. Although the number of traits has increased by one, what has happened to the number of possible phenotypes of offspring produced in the F2 generation? ni llit asa2013 bhidydenom sih at Simons 1:11 sabrax gatame
- Question 3 Review Mendelian genetics. Match the term and its description. Each term can only be used once. The two alleles for a heritable character separate (segregate) during gamete formation and end up in different gametes | Choose ) Each pair of alleles segregates independently of any other pair of alleles during gamete formation [ Choose ] An organism with two identical alleles for a character [ Choose ] an organism's physical appearance | Choose ) the breeding the mystery individual with a homozygous recessive individual [ Choose ) > > > > >Genetics (Study of genes) O a. All the other choices are valid O b. Our traits can be controlled by one or more genes O c. It is the study of the mode of transmission of genes from one generation to the next. O d. There are in general two copies of each gene called alleles in every diploid cell, with one allele on each homologous chromosome. If you get blue-black upon adding IKI to a substance, then this substance is a protein or a polypeptide O a. True O b. FalseQuestion 6 Review non Mendelian genetics. Match the term and its description. Each term can only be used once. the phenotype of F1 hybrids is somewhere between the phenotypes of the two parental varieties | Choose | two dominant alleles affect the phenotype in separate and distinguishable ways | Choose | Most genes exist in populations in more than two allelic forms | Choose | Most genes have multiple phenotypic effects [ Choose J multiple genes independently affect a single trait | Choose | expression of a gene at one locus alters the phenotypic expression of a gene at a second locus [ Choose J > > > >
- Monohybrid Problems llustrating Codominamce 5. Another type of monohybrid inheritance involves the expression of both phenotypes in the heterozy- gous situation. This is called codominance. One well-known example of codominance occurs in the coat color of Shorthorn cattle. Those with reddish-gray roan coats are heterozygous (RR'), and result from a mating between a red (RR) Shorthorn and one that's white (R'R'). Roan cattle don't have roan-colored hairs, as would be expected with incom- plete dominance, but rather appear roan as a result of having both red and white hairs. Thus, the roan col- oration is not a consequence of pigments blending in each hair. Because the R and R' alleles are both fully expressed in the heterozygote, they are codominant. a. If a roan Shorthorn cow is mated with a white bull, what will be the genotypic and phenotypic ratios in the F, generation? genotypic ratio . phenotypic ratio b. List the parental genotypes of crosses that could produce at least some…QUESTION 5. The pedigree below follows the appearance of a rare autosomal dominant condition resulting in malformation of limbs through a family. What is the penetrance of this trait? i.e., What is the ratio between the number of individuals in the pedigree who display the trait (numerator) and the number of individuals you know from the pedigree must have the trait-determining genotype (denominator)? Enter your answer in the form of a fraction without any spaces. e.g., If your answer is “one-fourth”, enter: 1/4Use this information to answer the next two questions. Multiple alleles control the coat colour of rabbits. ● The dominant allele, C, produces grey colour. The Coh allele produces silver grey (chinchilla) colour when homozygous. The Challele is recessive to both the full colour allele and the chinchilla allele. ● ● The Challele produces a white colour with black extremities (Himalyan) The Ca allele is recessive to all other alleles, and produces no pigment (albino). The dominance hierarchy is C> Cch > Ch > Ca. The table below provides the possible genotypes and phenotypes for coat colour in rabbits. Notice that four genotypes are possible for full-colour but only one for albino. Phenotypes Full Colour Chinchilla Light grey Himalayan Albino JUL Genotypes CC, CCch, Cch, CCª Cch Coh Question 2 (2.5 points) In the first cross, a rabbit with the chinchilla coat colour is mated to a rabbit with a Himalavan coat colour that is known to be homozygous for this trait Calculate the 25 tv MIZA…
- QUESTION 1 Exceptions to Mendel's Rules Matching. Match the exception to Mendel's rules with the example that illustrates it. human body shape is controlled by a number of genes children heterozygous for Tay-Sachs disease make about 50"% of v the normal healthy enzyme, homozygous recessive individuals make 0% and homozygous dominant individuals make 100% A. incomplete dominance diabetes, ultraviolet light, and alcoholism cause cataracts (cloudy v eyes) that are coded for by a dominant allele to develop earlier and B. codominance more severely C. epistasis a dominant allele codes for cataracts (cloudy eyes) but another allele affects how bad the cataract will be D. environmental effects on gene expression homozygous cattle are brown or white while heterozygotes have both brown and white hair E. pleiotropy F. polygenic men with the gene for goutare eight times more likely than women to develop a severe case G. sex linkage the human disease Marfan Syndrome results from a gene that affects…Please answer fast You obtain the following number of offspring in a test cross of a dihybrid plant with a test cross parent with the given phenotype. The test cross is: Tt Pp x tt pp the expected phenotypic ratio 1:1:1:1 what is the chi-square value for this chi-square? Tall purple flower: 36 Tall white flower: 37 Short white flower: 34 short purple flower : 33GENETICS PROBLEMS . In pea plants, yellow seeds (Y) are dominant and green seeds (y) are recessive. Assume that a cross was performed between two plants that are each heterozygous seed color. for a. Complete the Punnett square for the cross. Y- yellow y -green b. Write the genotypic ratio for the offspring from this cross. C. Write the phenotypic ratio for the offspring from this cross. (F) is deminant. Assume that a homozygous recessive