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Q7: When the input to a given system audio is (4 cos 800 tt + cos 2000tt) mv, the measured frequency component at 600 kHz is 1mv. Represent the amplifier output – input characteristic by e, = aze; + aze? and calculate the numerical values of a1 and a2 from the data given. Ans: aj = 1000; a2 = 250 vl.

Q7: When the input to a given system audio is (4 cos 800 tt + cos 2000tt) mv, the measured frequency component at 600 kHz is 1mv. Represent the amplifier output – input characteristic by e, = aze; + aze? and calculate the numerical values of a1 and a2 from the data given. Ans: aj = 1000; a2 = 250 vl.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Type your question here When the input to a given system audio is (4 cos 800 ?? + ??? 2000??) ??, the measured frequency component at 600 ??? is 1mv. Represent the amplifier output – input characteristic by ?? = ?1?? + ?2?? 2 and calculate the numerical values of ?1 and ?2 from the data given.
Q7: When the input to a given system audio is (4 cos 800 tt + cos 2000nt) mv, the measured frequency component at 600 kHz is 1mv. Represent the amplifier output – input characteristic by e, = a¡e¡ + azef and calculate the numerical values of a, and a, from the data given. Ans: aj = 1000; a2 = 250 v-l.
Transcribed Image Text:Q7: When the input to a given system audio is (4 cos 800 tt + cos 2000nt) mv, the measured frequency component at 600 kHz is 1mv. Represent the amplifier output – input characteristic by e, = a¡e¡ + azef and calculate the numerical values of a, and a, from the data given. Ans: aj = 1000; a2 = 250 v-l.
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