Pb-3b, A circular column has to be designed using lateral ties to carry an axial load of 1500kN. Using M25 mix and Fe 415 grade steel, what is the required diameter of column section? (assume longitudinal steel percentage = 1% of gross area) -
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- Q2 1- Check the following weather one way or two way 2- Calculate the design ultimate load Wu on the on the beams B3, B6 Assume slab load: Live load = 5 kN/m2 Dead load = 8 kN/m? Beam size 300x500 mm %3D B5 B6 B7 3.6 m |L 4.8 4 m 5m 5m BI B2 B4Q- A circular column has to be designed using lateral ties to carry an axial load of 1500kN. Using M25 mix and Fe 415 grade steel, what is the required diameter of column section? (assume longitudinal steel percentage = 1% of gross area).1. A steel column 10 m long is fabricated from a cover plate and C section arranged as shown. Determine the safe compressive load. Fy = 248 MPa, E= 200 GPa. Use AISC/NSCP Specs. 450 mm -cover plate 'I 12 mm y2 IP d2 10 m C 310 x 37 A = 4720 mm? d = 305 mm bf = 77 mm tf = 12.7 mm tw = 9.8 mm C 310 X 37 a) Both ends of column are fixed b) Both ends of column are hinged c) One end fixed, the other end hinged Use design values of k. tw d=305- Ix = 59.9x10° mm ly = 1.85x10° mm x = 17.1 mm x=17.1
- Details of a rectangular column are as follows: Column width along X-axis-250 mm Column Depth along the Y-axis-600 mm 8-25 mm diameter bars distributed equally along the longer sides. 10 mm diameter ties spaced at 10 mm on centers Concrete 28th day Compressive strength, fc;=20.7 MPa Reinforcing Steel yield strength, fy-415 MPa Assume that compression steel yields. a) Which of the following gives the nominal balanced load Pb (kN). A = 90.4 mm b) Which of the following gives the nominal axial load (kN) that the column n carry at an eccentricity of 200 mm along the X axis from the centroidal Y-axis.Pls. AnswerGiven: f'c = 35 MPa fy= 415 MPaSolve for Slab S-1 (only)The below figure represents a section of a pre- stressed beam. For a no-tension design where a is the permissible stress in concrete, the total moment carrying capacity is (a) (c) d/2 bd² 6 d/2 bd²oc 3 -b- (b) (d) bd² oc 4 bd²a 12
- RCDA reinforced concrete T- beam, section in Figure 2 (a), is subjected to an ultimate uniformload and concentrated loads as shown in the Figure 2(b). The beam is reinforced with 6-28 mm diameter tension bars at the point of maximum positive moment (at midspan -bars at the bottom), and 3-28 mm diameter tension bars at the point of maximum negativemoment (at the supports - bars at the top) .. The design properties used are: f ‘c = 21MPa and fy = 414 MPa, ; flange width = 650 mm, flange thickness is = 90 mm; webthickness = 250 mm; effective depth = 410 mm.Need to answerQ. Draw the shear and moment diagrams for the given loads;1) Column AB is made of solid 410, cold worked Steel with the following specification Sy=85 KSI, E-29000 KSI Length: 9.5 in. Diameter: 425 in. Ends: Free & Fixed For the above column calculate: a) Type of column failure (show proof) b) The critical load that would cause failure. c) Allowable force with Factor of Safety of 2.5. Answer Unit Value a 13 14 14A rectangular beam 250 mm wide, 500 mm deep is reinforced at the bottom with d-20-mm-dismeter bars and at the top with 2-16-mm bars. Concrete cover to bar centroid at the top is M0 mm and at the bottom is 70 mm. Use concrete strength r'e-21 MPa und steel yield strength fy 415 MPa for 20- mm bars and fy= 275 MPA for 16 mm bars Detenmine the design moment capacity n kN m of the beam in negative bending. A 40.06 O45.07 C. 42.70 D47.55
- Problem 01 Using ASD, check the adequacy of the base plate (PL400X350×19 mm) centered on a W12X152 column as shown. It is resting on a concrete pedestal that is 450 mm x 400 mm. The loads are PDL = 600KN and PLL = 320 kN. Use A-36 steel and concrete fc'=20 MPa. THA3. A composite beam and deck system made up of W360x72 at 1000mm o.c. is to span 8m. The deck when cast is to be 100mm thick concrete (25MPA). The shear studs to be used have an ultimate stress capacity of 415MPA and will have a diameter of 16mm. Assuming 100% connection and that the system is shored during casting determine the ultimate moment of the composite W360.A simply supported beam spans 8 m. It carries the uniformly distributed load throughout of its length. Dead Load, D = 15 kN/m (beam weight not included) %3D Live Load, L = 10.8 kN/m Given: Beam section: W460 x 97 kg/m Area - 12, 320 mm? Depth, d - 465 mm %3D Flange width, bf = 193 mm Web thickness, t = 11 mm !! Flange thickness, t - 19 mm Zx - 1.89 x 106 mm Zy - 2.18 x 10° mm E-200,000 MPa Fy- 345 MPa