Let a grade file be any file in the following format: Student Number, Grade 101029383,80 192736611,0 292833315,51 109800384, 100 Complete the function below such that it constructs and return a dictionary that maps student numbers to grades. def make_dictionary (file_name: str) -> Dict [str, int]: """Given the name of a grade file file_name, return a dictionary that maps student numbers to grades. Assuming "grades.txt" contains the four records in the example file above >>> d = make_dictionary ("grades.txt") >>> d["101029383"] 80 >>> d["292833315"] 51 >>> len (d) 4 ||||||

Let a grade file be any file in the following format: Student Number, Grade 101029383,80 192736611,0 292833315,51 109800384, 100 Complete the function below such that it constructs and return a dictionary that maps student numbers to grades. def make_dictionary (file_name: str) -> Dict [str, int]: """Given the name of a grade file file_name, return a dictionary that maps student numbers to grades. Assuming "grades.txt" contains the four records in the example file above >>> d = make_dictionary ("grades.txt") >>> d["101029383"] 80 >>> d["292833315"] 51 >>> len (d) 4 ||||||

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def most_total(bdm): '''(dict of {str: dict of {int: list of str}}) -> str bdm is a birthday month dictionary with at least one key. Return the name of the month with the most total days on which someone has a birthday. If there is a tie, return any month with that maximum. >>> d = {"Jan": {1: ["Steve"], 5: ["Bob"], 31: ["Ron"]}, "Aug": {1: ["Jim", "Tim"], 24: ["Sadia", "Tony"]}} >>> most_total(d) 'Aug' '''
def animals(animal_dict, target): """ Filter animals based on the target category. :param animal_dict: A dictionary mapping animals to their categories. :type animal_dict: dict :param target: The target category to filter animals. :type target: str :return: A list of animals belonging to the target category. :rtype: list animals_dict = {"dogs": "mammals", "snakes": "reptiles", \ "dolphins": "mammals", "sharks": "fish"} >>> target = "mammals" >>> animals(animals_dict, target) ['dogs', 'dolphins'] >>> animals_dict = {True: "mammals"} >>> animals(animals_dict, target) # This will raise an AssertionError Traceback (most recent call last): ... AssertionError: Target should be provided and not None """ assert target is not None, "Target should be provided and not None" assert isinstance(animal_dict, dict) assert all(isinstance(animal, str) for animal in animal_dict.keys())…
def animals(animal_dict, target): """ Filter animals based on the target category. :param animal_dict: A dictionary mapping animals to their categories. :type animal_dict: dict :param target: The target category to filter animals. :type target: str :return: A list of animals belonging to the target category. :rtype: list animals_dict = {"dogs": "mammals", "snakes": "reptiles", \ "dolphins": "mammals", "sharks": "fish"} >>> target = "mammals" >>> animals(animals_dict, target) ['dogs', 'dolphins'] >>> animals_dict = {True: "mammals"} >>> animals(animals_dict, target) # This will raise an AssertionError Traceback (most recent call last): ... AssertionError """ assert target is not None, "Target should be provided and not None" assert isinstance(animal_dict, dict) assert all(isinstance(animal, str) for animal in animal_dict.keys()) assert all(isinstance(category, str) for…
def city_dict(adict): """ Question 6 -Given a dictionary that maps a person to a list of countries they want to travel to, return a dictionary with the value being the list sorted by the last letter in each countries name. If two countries have the same last letter, sort by the first letter. -For an extra challenge, try doing this in one line (Optional). Args: adict (dict) Returns: dict >>> city_dict({"Pablo": ["Belgium", "Canada", "Germany"], "Athena": ["Italy", "France", "Egypt"], "Liv": ["Japan", "Bolivia", "Greece"]}) {'Pablo': ['Canada', 'Belgium', 'Germany'], 'Athena': ['France', 'Egypt', 'Italy'], 'Liv': ['Bolivia', 'Greece', 'Japan']} >>> city_dict({"Jacob": ["Bahamas", "Brazil", "Chile"], "Lexi": ["Colombia", "Finland", "Panama"], "Emily": ["Ireland", "Russia", "Kenya", "Jordan"]}) {'Jacob': ['Chile', 'Brazil', 'Bahamas'], 'Lexi': ['Colombia', 'Panama', 'Finland'], 'Emily': ['Kenya',…
get_movie_dict() takes a 2-D list similar to movie_db and a dictionary similar to ratings as the parameters and returns a dictionary, where each {key: value} of this dictionary is {a valid movie id: a list containing the name of the movie, the year it got released, and the average rating of this movie}. I will refer to this dictionary as movies.>>> movies = get_movie_dict(movies_db, ratings)>>> display_dict(movies)1: ['Toy Story', 1995, 3.92]2: ['Jumanji', 1995, 3.43]3: ['Grumpier Old Men', 1995, 3.26]4: ['Waiting to Exhale', 1995, 2.36]5: ['Father of the Bride Part II', 1995, 3.07]6: ['Heat', 1995, 3.95]7: ['Sabrina', 1995, 3.19]8: ['Tom and Huck', 1995, 2.88]9: ['Sudden Death', 1995, 3.12]10: ['GoldenEye', 1995, 3.5]11: ['American President The', 1995, 3.67]12: ['Dracula: Dead and Loving It', 1995, 2.42]13: ['Balto', 1995, 3.12]14: ['Nixon', 1995, 3.83]15: ['Cutthroat Island', 1995, 3.0]16: ['Casino', 1995, 3.93]17: ['Sense and Sensibility', 1995, 3.78]18: ['Four…
void dict_clear (dict_t* dict); This function clears the dictionary dict, destroying each pair key/value, but does not destroy dict itself (remember that dict was allocated using dict_create, so it will need to be freed at some point, but this is not this function’s job.) This is now the function that frees (destroys) a dictionary: void dict_destroy (dict_t* dict); This operates just as dict_clear, but in addition should free the memory that was allocated during dict_create. After a call to this function, if any other library function receives the pointer dict, the behavior is undefined (most likely, it will crash). This simple function returns the current size of the dictionary: size_t dict_size (const dict_t* dict);
def list_to_dictionary(t): """ t is a list of values (values could be str, list, tuple, set, dictionary), create and return a dictionary such that the key is len(v) for some v in t, and the value is a list of values [v1, v2, ...] from t (in the order they appeared in t) whose len(vi) is the key. for example: if t = [(1,2,3), "abc", [1, 2], (), ""] then return value of this function should be: {3: [(1, 2, 3), 'abc'], 2: [[1, 2]], 0: [(), '']} """
Homework Assignment-1Topics: Functions, Dictionary, ImportProblem description: Write a python application to simulate an online clothing system. Thepurpose of this assignment is to gain experience in Python dictionary structure, create basicPython functions and import a module.Design solution: The template file contains a list of clothes item sold, each item in the listcontains the item id, name of the item and the prices. The program will generate an items_dictwhere each key is the item id of the cloth and the values will be a list of item name and priceinformation. A customer will be presented with a main menu with 4 different options: displayall items, add an item to cart, checkout and exit the program. A customer can buy an item byentering the ID of the item. This program implements a dictionary called cart, where each key isthe item id and the values are the list of name, price and quantity that user chooses topurchase. The program keeps repeating by displaying the main menu to…
This is my code for a dictionary of student's test scores. def main(): #Create a dictionary with name as key #Marks as the list of values student_dictionary = \ { 'Brian': [94, 89, 92], 'Rachel': [100,90,65], 'Jon': [67.5,95,100], 'Brit': [0,78,80] , 'Gret': [65,100,78], 'Andrea': [55.5,67,79] } for key in student_dictionary.keys(): print('Name: ', key, " , Marks:", student_dictionary.get(key)) if __name__ == '__main__': main() Problem: Find and print out Rachels second score (should be a 90)
Find Country Function Name: findCountry() Parameters: capitalList ( list ) Returns: Dictionary mapping each capital to its country( dict ) Description: Given a list of countries' capital cities, write a function that returns a dictionary that maps a capital to its country's name. Note: Assume that all capital cities provided are valid. example test cases: >>> findCountry(('tokyo', 'delhi', 'stockholm']) {'tokyo': 'Japan', 'delhi": 'India', 'stockholm': 'Sweden'} >>> findCountry(l'paris', 'canberra', 'copenhagen']) {'paris': 'France', 'canberra': 'Australia', 'copenhagen': 'Denmark'} For this assignment, use the REST countries API (https://restcountries.com/#api-endpoints-v2). For all of your requests, make sure you to use version 2 of the REST countries API (V2), not version 3 (V3.1). If you make a request with the URL: https://restcountries.com/v2/alpha/usa, you will receive the following response: { "name": "United States of America", "topLevelDomain": [".us"], "alpha2Code": "US",…
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def drop_uninformative_objects(X, y):# your code herereturn X_subset, y_subset # TEST drop_uninformative_objects functionA = pd.DataFrame(np.array([[0, 3, np.nan],[4, np.nan, np.nan],[np.nan, 6, 7],[np.nan, np.nan, np.nan],[5, 5, 5],[np.nan, 8, np.nan],]))b = pd.Series(np.arange(6))A_subset, b_subset = drop_uninformative_objects(A, b) assert A_subset.shape == (3, 3)assert b_subset.shape == (3,)