Joe is heterozygous for a dominant genetic disease. His wife, Jenny does not have thedisease. They have 5 children of which 2 (Jim and Jan) have the disease and 3 (Jose,Jerry and Julie) do not. DNA from each individual is isolated and analyzed by PCR angel electrophoresis. 3 variable markers are studied. The results for each marker areshown here. The numbers to the left of each gel represent size in hundreds of basesJim JoseMarker 1Marker 2Marker 1Jenny JoeMarker 3Jan Jerry JulieJim JoseMarker 2JennyJoeJan Jerry JulieJim JoseMarker 3Jenny JoeBased on these results, which marker is mostlikely associated with the condition?JanJerryJulie Question40 ListenFor isolation of DNA from small amounts ofdinosaur bone you would usePCRGel electrophoresisCrisprQuestionRestriction enzymes▶◄ ListerFor cutting DNA at specific sequences you wouldusePCRGel electrophoresisRestriction enzymesCrispri

Hansbsb In order to establish that a marker is responsible for the disease, it must be present in…

Joe is heterozygous for a dominant genetic disease. His wife, Jenny does not have the disease. They have 5 children of which 2 (Jim and Jan) have the disease and 3 (Jose, Jerry and Julie) do not. DNA from each individual is isolated and analyzed by PCR an gel electrophoresis. 3 variable markers are studied. The results for each marker are shown here. The numbers to the left of each gel represent size in hundreds of bases 4321 4321 Jim Jose Marker 1 Jenny Joe Jan Jerry Julie 8321 Jim 8321 I Marker 2 Jenny Joe Jose Jan Jerry I Julie Jim Jose - Marker 3 Jenny Joe Jan Jerry Julie

Joe is heterozygous for a dominant genetic disease. His wife, Jenny does not have the disease. They have 5 children of which 2 (Jim and Jan) have the disease and 3 (Jose, Jerry and Julie) do not. DNA from each individual is isolated and analyzed by PCR an gel electrophoresis. 3 variable markers are studied. The results for each marker are shown here. The numbers to the left of each gel represent size in hundreds of bases 4321 4321 Jim Jose Marker 1 Jenny Joe Jan Jerry Julie 8321 Jim 8321 I Marker 2 Jenny Joe Jose Jan Jerry I Julie Jim Jose - Marker 3 Jenny Joe Jan Jerry Julie

Biology Today and Tomorrow without Physiology (MindTap Course List)

5th Edition

ISBN:9781305117396

Author:Cecie Starr, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Christine Evers, Lisa Starr

Chapter10: Biotechnology

Section: Chapter Questions

Problem 1VQ

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The following figure shows the FBI-style analysis of the genomic DNA of 10 people (1-10), and also of hair found at a crime scence left by the murderer [***]. This analysis involves the PCR amplification of SSR loci, each from a different (nonhomologus) chromosome. The PCR primers are for each SSR locus are labeled with a unique fluorescent molecule. Some bands are thicker because relatively more of the corresponding PCR product was obtained. The figure has dots aligned on both sides to help you find the crucial bands; it will help to use a straight-edge as a guide. The numbers at right are the total number of copies of the SSR locus among the population of 11 samples. e. What is the probability that any random male in USA would share the same genotype as the murderer (the match probability)? Assume that all 11 DNA samples analyzed in the diagram are together representative of the USA population as a whole. Show what numbers you would multiply to do this calculation.
The following figure shows the FBI-style analysis of the genomic DNA of 10 people (1-10), and also of hair found at a crime scence left by the murderer [***]. This analysis involves the PCR amplification of SSR loci, each from a different (nonhomologus) chromosome. The PCR primers are for each SSR locus are labeled with a unique fluorescent molecule. Some bands are thicker because relatively more of the corresponding PCR product was obtained. The figure has dots aligned on both sides to help you find the crucial bands; it will help to use a straight-edge as a guide. The numbers at right are the total number of copies of the SSR locus among the population of 11 samples. Are any of individuals 1-10 probable relatives of the murderer? If so, identify this person and describe the degree of relationship to the criminal.
The following figure shows the FBI-style analysis of the genomic DNA of 10 people (1-10), and also of hair found at a crime scence left by the murderer [***]. This analysis involves the PCR amplification of SSR loci, each from a different (nonhomologus) chromosome. The PCR primers are for each SSR locus are labeled with a unique fluorescent molecule. Some bands are thicker because relatively more of the corresponding PCR product was obtained. The figure has dots aligned on both sides to help you find the crucial bands; it will help to use a straight-edge as a guide. The numbers at right are the total number of copies of the SSR locus among the population of 11 samples. Are any of the loci on the Y chromosome? If so, identify this (these) locus (loci) by color.
The following figure shows the FBI-style analysis of the genomic DNA of 10 people (1-10), and also of hair found at a crime scence left by the murderer [***]. This analysis involves the PCR amplification of SSR loci, each from a different (nonhomologus) chromosome. The PCR primers are for each SSR locus are labeled with a unique fluorescent molecule. Some bands are thicker because relatively more of the corresponding PCR product was obtained. The figure has dots aligned on both sides to help you find the crucial bands; it will help to use a straight-edge as a guide. The numbers at right are the total number of copies of the SSR locus among the population of 11 samples. Are any of the loci on the X chromosome? If so, identify this (these) locus (loci) by color.
A blood stain from a crime scene and blood samples from four suspects were analyzed by PCR using fluorescent primers associated with three STR loci: D3S1358, vWA, and FGA. The resulting electrophoretograms are shown below. The numbers beneath each peak identify the allele (upper box) and the height of the peak in relative fluorescence units (lower box). Solve, (a) Since everyone has two copies of each chromosome and therefore, two alleles of each gene, what accounts for the appearance ofonly one allele at some loci? (b) Which suspect is a possible source of the blood? (c) Could the suspect be identifi ed using just one of the three STR loci? (d) What can you conclude about the amount of DNA obtained from Suspect 1 compared to Suspect 4?
The gel above shows 7 alleles, in this sample of 11 individuals, what percentage of individuals are homozygous? Please type your answer as a number, rounded to the nearest whole percentage. ANSWER: In the gel image below Blank 1 percent of the individuals are homozygous. Photograph of UV illuminated 1 % agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) 2000 1650 1000 850 600 500 Key: Lane 1: Lanes 2-12: A B C D E F G H I J K DNA ladder, see image for fragment sizes in base pairs (bp) PCR Products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K)
As the leading scientist in a biomedical science laboratory, it is a requirement to give advice to your lab assistants when they are having problems with their experiments. What advice would you give to your assistants that are having the following problems: After performing a polymerase chain reaction (PCR) and agarose gel electrophoresis to confirm the presence of the C01 gene of 750bp. 2.1. They observe no band appearing on an agarose gel. What would be your conclusion? 2.2. They observe three bands of different sizes that resemble a smear on the gel. Advice 2.3. They observe a single band on the gel and conclude that the PCR product is an exact copy of the original template DNA. Would you support their condusion? Explain. 2.4. Explain how PCR can be used to detect infectious agents in diagnoses of diseases.
Four E. coli strains of genotype a+ b- are labeled 1, 2, 3, and 4. Four strains of genotype a- b+ are labeled 5, 6, 7, and 8. The two genotypes are mixed in all possible combinations and (after incubation) are plated to determine the frequency of a+ b+ recombinants. The following results are obtained, where M = many recombinants, L = low numbers of recombinants, and 0 = no recombinants:On the basis of these results, assign a sex type (either Hfr, F+, or F-) to each strain.
DNA obtained from the indicated donor strains is used to TRANSFORM the indicated recipient strains. The resulting progeny are plated on minimal medium so that only wild-type recombinants are scored. The number of wild-types for each cross is given in the chart below. donor donor arg+ val- ser- val+ ser- arg- val- ser+ val- ser+ arg+ val- ser- O valine recipient recipient none of these. O arginine arg- val+ ser+ arg+ val- ser+ Which locus is closest to serine? arg+ val+ ser- wild-types wild-types 70 98 0 2 arg- arg-
Nikolas is investigating the presence of four different genes (A, B, C and D) in Ladybugs using a PCR technique illustrated below (Figure 2). Deduce FOUR (4) possible reasons why this method is utilized rather than the conventional PCR technique. +1 A 422 318 275 232 181 109 B * Marker PCR with all four primer pairs in a single tube 371 275 202 141 Figure 2 Ꭰ
Why is the company Qiagen has more refined DNA extraction steps than a normal Strawberry DNA extraction practical? Summary of Qiagen DNA extraction steps Add ATL buffer and grind with sample. Add 20 microliters of enzyme Proteinase K to degrade protein into a 1.5-2ml microcentrifuge tube. Add 200 microlitres AL lysis buffer, and mix by vortexing for 5–10 seconds, which breaks cell membrane allowing DNA to be released. Incubate the sample at 56 degrees for 10 minutes. Mix the cell lysate with 200 microlitres ethanol by pipetting it at the side of the microcentrifuge wall so DNA precipitates. The DNA forms a white layer and the remaining liquid is discarded. Pipet the mixture into DNeasy Mini spin column placed in a 2 ml collection tube. Centrifuge for a minute at 8000 rpm. Place the mini spin column into a 2 ml collection tube, add 500 µl Buffer AW1, and centrifuge for 1 min at 8000 rpm. Then add it to a new 2 ml collection tube (provided), add 500 µl Buffer AW1, and centrifuge for 1…
Here is a DNA agarose gel showing PCR products from a mouse genotyping experiment. Genotyping tells us whether each mouse is a wild type mouse (i.e. not genetically modified) or a mutant mouse. Interpret the results for each mouse 1-3.