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- Find an equation of the tangent line to the curve at the given point.y = 4x^2 − x^3, (1, 3) Illustrate by graphing the curve and the tangent line on the same screen.Find the equation of the line tangent to the function at the given point. Your answer should be in slope intercept form y=x^3-2x^2+2 at (2,2)|Find an equation of the tangent line to the curve at the given point. Y= x^3 -3x+2, (2,4)
- find an equation of the tangent line that passes through y=x^3+x+4 at (-(2,-6)Find the slope and an equation of the tangent line to the graph of the function f at the specified point. F(x)= -9/2x^2+4x+4; (-1,-9/2) slope= equation y=Find the equation of the tangent line to the curve y= 3x^2 - 2 passing through the point P(-1,1) .