In the given i-v characteristic below, which load line represent the given circuit? I-V curve for a Typical Diode 1 3 0.4 0.6 0.8 Voltage [V] Current [mA] 10 8 6 4 2 0 1 2 3 5 0 0.2 2 1 6V. E Σ1 ΚΩ
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- How is a solid-state diode tested? Explain.In the circuit shown below. Determine the following a. Vs (at the secondary) b. Vout (across RL) c. Vrip (ripple votage) d. VDC e. PIV (Peak Inverse Voltage) 10:1 Output 115 V mis 60 Hz RL 2.2 k) D, 50μF- All diodes are IN4001. Tund AlMannai EENG261 Page 5/11consider the figure below that shows an approximated reverse recovery turn-off characteristics for a power diode. Show that the following relation can express the total reverse recovery charge, Qrr = 1/2(trr*ts1) di1/dt =1/2(trr*ts21) di2/dt * ip Isl 1s2! -Ir
- Given the following circuit with VDD= 9.2 V, R=2.3 k2, then the current Iis: Use the CVD model for the diode, with VD = 0.65 V. I VDD a. 0.004000 A O b. 3.717391 A OC. 0 A d. 4.000000 A e. 0.003717 A R + VD -Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as germanium and D2 as silicon diodes. Input Vpp%3D20V, V1=3 V and V2=10 V. R D2 D1 Vin Vout V1 V2 Maximum voltage of output waveform Minimum voltage of output waveform PsIn the clamping circuit below, assume the diode has Von-0.7V and V₁ is a sinusoidal wave with a peak-to-peak amplitude of 10V. How much is the maximum value of the output voltage signal (Vmax)? And how much will it be if we set V₂=2V? Input V1 C1 0.1e-6 9.3 V and 7.3 V 9.3 V and 11.3 V 11.3 V and 7.3 V O 7.3 V and 12.0 V O 12.0 V and 7.3 V Output D1 1N4148 .tran 30-3 V2 0 Vmax V(output) 0.0ms putput MAN Input 0.6ms 1.2ms V(input) 1.8ms 2.4ms 3.0ms
- Draw the input waveform and output waveform for the circuit given below with proper values marked in the figure. Assume D1 as silicon and D2 as germanium diodes. Input Vpp=20V. V1=5 V and V2=9 V. R www D1 Vin Vout v1 V2 Maximum voltage of output waveform Minimum voltage of output waveformIn the circuit of the following figure, the input voltage Vs is 15 volts rms with a frequency of 60 Hz, R equals 150 Ohms and C equals 100,000 Pico Farads. The diodes are Germanium (Vd = 0.2 volts) and the Zener diode is 12 volts. a) The magnitude of the ripple voltage at Cb) The Magnitude of the Peak Inverse Voltage (PIV) for D1 and D2.For the circuit shown in the Figure, if the diodes are silicon diodes with VD(on)=0.7 V, and VIn=50 sin wt V, V1 =7 V and V2 =13 V, then the value of VOUT (p-p) is: R1 D, D2 VIN VOUT vi E v2= Ca. 19.4 V Ob. 17.4 V Cc. 15.4 V Cd. 21.4 V
- Q4) Determine and sketch the output voltage across the load resistor (RL) for the circuit shown below. (assume Si diodes) V_DC 0.75 0.25 V_SIN Y SIN as RL -1 v SOR V_SQR 0.75 -0.75 V_TRI V TRI asPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20V2. Figure A.1 shows I-V characteristics of two diodes, namely A and B. Diode A has higher dynamic resistance than diode B. UTM &UT ID 4 5UTM 3TM UTM UTM &UTM 5 UTM & UTM UTM 3 UTM 03 TM 6 UT 0.68 (a) UTM VD Figure A.1 State one possible reason why the diodes have different knee voltage values. UTM OM & UTM 3 UTM & TM (b) Based on Figure A.1, identify the knee voltage of UTM" TM 5 UTde BE UTM