In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B) are dominant to red eyes (b). A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype ggbb. What percent of the offspring will have white fur and red eyes? Select one: 25% 50% 100% 0%
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- PRISCILLA TORRES Mendelian Genetics [6F.R]:Question 2 In fruit flies, red eyes (R) are a dominant trait and white eyes (r) are recessive. If a homozygous red eyed fly was crossed with a white eyed fly, what percent of the offspring would be homozygous recessive? Select one: 50% 100% 25% DELItype P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONS# 2 a) If sex and eye colored were viewed as two different phenotypes with male being dominant over female (or vice versa), then Mendelian ratios of a dihybrid cross may explain the ratios that Morgan got. Here is some hypothetical data based on the ratios gotten by Morgan and the expected Mendelian ratios for a dihybrid F1 cross. Perform a Chi-square test (separate scrap paper) with the null hypothesis being that the "Morgan observed ratios" are within chance from the Mendelian ratios. State whether the Chi-square test supports or rejects the null hypothesis and explain. (Be sure t include the X2 value, degrees of freedom, critical value.) Hint: what did Morgan discover? Think about this for your degrees of freedom. * Expected Mendelian Ratios Morgan Observed Ratios 900 Red, male 800 Red, male 300 Red, female 400 Red, female 400 white, male 300 white, maile O white, female 100 white, female Schoology Support | Schoology Blog | PRIVACY POLICY | Terms of Use INTL
- #2 a) If sex and eye colored were viewed as two different phenotypes with male being dominant over female (or vice versa), then Mendelian ratios of a dihybrid cross may explain the ratios that Morgan got. Here is some hypothetical data based on the ratios gotten by Morgan and the expected Mendelian ratios for a dihybrid F1 cross. Perform a Chi-square test (separate scrap paper) with the null hypothesis being that the "Morgan observed ratios" are within chance from the Mendelian ratios. State whether the Chi-square test supports or rejects the null hypothesis and explain. (Be sure to include the X2 value, degrees of freedom, critical value.) Hint: what did Morgan discover? Think about this for your degrees of freedom.* Expected Mendelian Ratios Morgan Observed Ratios 900 Red, male 800 Red, male 300 Red, female 400 Red, female 300 white, male 400 white, male O white, female 100 white, female Terms of Use Support | Schoology Blog | PRIVACY POLICY IN(D) 1/6 (E) 1/64 26. In sheep, eye color is controlled by a single gene with two alleles. When a homozygous brown-eyed sheep is crossed with a homozygous green-eyed sheep, blue-eyed offspring are produced. If the blue-cyed sheep are mated with each other, what percent of their offspring will most likely have brown eyes? (A) 0% (В) 25% (C) 50% (D) 75% (E) 100% 27. In peas the trait for tall plants is dominant (T) and the trait for short plants is recessive (t). The trait for yellow seed color is dominant (Y) and the trait for green seed color is recessive (y). A cross between two plants results in 296 tall yellow plants and 104 tall green plants. Which of the following are most likely to be the genotypes of the parents? (A) TTYY x TTYY (В) Туу х ТТYу (C) TIYY x TIYy (D) TIYy x TTYY (E) TtYY x Ttyy 28. In humans, red-green color blindness is a sexlinked recessive trait. If a man and a woman produce a color-blind son, which of the following must be true? (A) The father is color-blind. (B)…O e. 1/8 QUESTION 3 In Mendel's pea plants, round shape (R) is dominant to wrinkled shape (r), and yellow color (Y) is dominant to green color (y). The alleles for seed shape and seed color sort independently. In the parental generation, Mendel crossed a true-breeding round, yellow-seeded plant with a true-breeding wrinkled, green-seeded plant to create an F1 generation. He then crossed the F1 offspring to eachother. What type of cross is this considered? O Dihybrid cross Heterozygous cross Testcross Genetic cross O Monohybrid cross QUESTION 4 - Save and Submit to save and submit. Click Save All Answers to save all answers. 20 000 OOD F4 MacBook Air
- Purple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口0 + + O O Coat color in cats is determined by genes at several different loci. At one locus on the X chromosome, one allele (X` ) encodes black fur and another allele (X) encodes orange fur. Females can be black (X X ), orange (X X ), or a mixture of orange and black called tortoiseshell (X X ). Males are either black (XY) or orange (XY). O Bill has a female tortoiseshell cat named Patches. One night, Patches escapes from Bill's house, spends the night out, and mates with a stray male. Patches later gives birth to the following kittens: one orange male, one black male, two tortoiseshell females, and one orange female. What are the genotypes of Patches, the stray male, and the kittens? Patches stray male orange male kitten black male kitten tortoiseshell female kitten orange female kitten + X Y Answer Bank 0 0 X X + + X X +0 X X 0 X YMendelian Genetics Punnett Square Question : In cattle, the hornless condition (H) is dominant to that for the possession of horns (h). a) A horned bull is mated to a hornless cow which is heterozygous . What kind of offspring are to be expected and in what ratio ? b) If the cow is then mated to a hornless bull which is also heterozygous, what is the chance that the first calf will have horns ? c) Assuming that the first calf has horns, what is the chance that the second calf will be hornless ?
- Chi-square Test In the pea plants use by Gregor Mendel in his study, the purple flower color is dominant over white,and the axial position on a branch is dominant over terminal. A plant believed to be heterozygouswas selfed and produced flowers with the following phenotypes: 23 white terminal68 white axial81 purple terminal187 purple axial a. assign alleles to the different traitspurple __________ axial ___________white ___________ terminal _______ b. refer to the image attachedIn the common daisy, genes A and B control flower color. Both genes have a dominant allele (A or B) and a recessive allele (a or b). At least one copy of each dominant allele is required for flowers to be colorful instead of white. (Explain and Justify your answers) 21.1) Predict the genotypes and phenotypes of the F1 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) AA bb, white B) aa BB, white C) Aa Bb, colorful D) Aa Bb, white E) aa bb, colorful 21.2) Predict the phenotypic ratio of the F2 progeny of a cross between two white-flowered plants, one homozygous AA and the other homozygous BB. A) 3 colorful : 1 white B) 9 colorful : 7 white C) 9 white : 7 colorful D) 15 white : 1 colorful E) 15 colorful : 1 white 21.3) The inheritance pattern of daisy flower color provides an example of what type of gene interaction? A) additivity…In a problem involving albinism (see Problem 4), which of Mendel’spostulates are demonstrated? Problem No. 4 Albinism in humans is inherited as a simple recessive trait.Determine the genotypes of the parents and offspring for thefollowing families. When two alternative genotypes are possible,list both.(a) Two parents without albinism have five children, four withoutalbinism and one with albinism.(b) A male without albinism and a female with albinism havesix children, all without albinism.