i. First, identify the acid. It's either H2PO41 or HPO42. The acid is because it has the most acidic hydrogens. ii. Then write the reaction for the acid dissolving in water + H20 HPO42 + H30*1 iii. Then write the expression for the Ka [HPO4?)[ H3O*1] Ka = iv. Then solve for [ H3O*l] and input the numbers Ka [ (6.20 x 108)( [ H30*l] = [HPO4?] (5.55 x 105) v. Finally calculate the pH pH = -log( A. H2PO41 В. НРОД? С. РОД3 D. H3PОД E. 6.20 x 108 F. 4.44 x 10-5 G. 5.55 x 105 Н. 4.96 x 10-8 I. 7,305
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
Buffers are solutions that buffer against large changes in pH when an acid or base is added. Buffers contain a weak acid to neutralize added base, and a weak base to neutralize added acid. Most buffer problems want you to calculate the pH. For example,
Calculate the pH of a buffer made from dihydrogen phosphate and hydrogen phosphate when the [H2PO4-1] = 4.44 x 10-5 M, the [HPO4-2] = 5.55 x 10-5 M, and the Ka = 6.20 x 10-8.
![i. First, identify the acid. It's either H2PO41 or HPO4?. The acid is
because it has the most acidic hydrogens.
ii. Then write the reaction for the acid dissolving in water
+ H20
HPO42
+ H30+1
iii. Then write the expression for the Ka
[HPO42][ H30*1]
Ka
iv. Then solve for [ H30*l] and input the numbers
Ką [
(6.20 х 10-8)
[ H30*l] =
[HPO42]
(5.55 x 10-5)
v. Finally calculate the pH
pH = -log(
) =
A. H2PO41
В. НРОД2
С. РОД3
D. H3PОД
E. 6.20 x 10-8
F. 4.44 x 10-5
G. 5.55 x 105
Н.
4.96 x 10-8
I. 7.305](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a9cf46f-1923-4110-8bfb-3c5048be5f9e%2F2496cc55-397f-4d5e-a4d2-a78a3e00509e%2F73vlqa_processed.png&w=3840&q=75)
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