Help me please I Review I CoThe magnitudes of the current density and the diameters for wires 1 and 2 are given in the table. The current directions are indicated by the arrows.Consider the juncion of three wires as shown in the diagram.(Figure 1)Current densityDiameterWire(A/mm2)(mm)13.22.05.93.5Part AFind the current Iz in wire 3.Express your answer in amperes to two significant figures. Call current out of the junction positive and current into the junction negative.• View Available Hint(s)VO AEO?I3 =AFigure1 of 1SubmitWire 1Part B Complete previous part(s)Wire 2Provide FeedbackWire 3

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I Review I Co The magnitudes of the current density and the diameters for wires 1 and 2 are given in the table. The current directions are indicated by the arrows. Consider the juncion of three wires as shown in the diagram. (Figure 1) Current density (A/mm?) Diameter Wire (mm) 3.2 2.0 2 5.9 3.5 Part A Find the current Is in wire 3. Express your answer in amperes to two significant figures. Call current out of the junction positive and current into the junction negative. > View Available Hint(s) να ΑΣφ I3 = A Figure < 1 of 1 Submit Wire 1 Part B Complete previous part(s) Wire 2 Provide Feedback Wire 3

I Review I Co The magnitudes of the current density and the diameters for wires 1 and 2 are given in the table. The current directions are indicated by the arrows. Consider the juncion of three wires as shown in the diagram. (Figure 1) Current density (A/mm?) Diameter Wire (mm) 3.2 2.0 2 5.9 3.5 Part A Find the current Is in wire 3. Express your answer in amperes to two significant figures. Call current out of the junction positive and current into the junction negative. > View Available Hint(s) να ΑΣφ I3 = A Figure < 1 of 1 Submit Wire 1 Part B Complete previous part(s) Wire 2 Provide Feedback Wire 3

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter9: Current And Resistance

Section: Chapter Questions

Problem 25P: The quantity of charge through a conductor is modeledas Q=4.00Cs4t41.00Cst+6.00mc .What is the...

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