>>>teams ["team1", "team2", "team3", "team4"] >>> rankings = [3, 2, 4, 1] >>> eliminate(teams, rankings, 1) ('team1', 'team2', 'team4')
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I'm still lost on how it works. From what I understand the code should do team 1 = 3rd place, team 2 = 2nd place, team 3 = 4th place, team 4 = 1st place. Then you filter out team 4 because you don't want anyone who ranked in that position. The output would then be: ('team1', 'team2', 'team3') but the test wants ('team1', 'team2', 'team4')?
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- Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…write code that assigns 1 to isAMember if the value of memberID can be found in current Members, and that assigns 0 to isAMemeber otherwise. Use only k, current Memebers, nMembers and isAMember. In C programming language
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