> Q. 6. The nomin I power of a shunt generator is 30 kW. The no output voltage of the generator is 240 V. The shunt field resistance is 50 2. The armature resistance is 0.1 wine are given as the rotor emf 255 V Toraparameters a and the mechanical power loss 1232 W. the winding operating point 55, the terminal voltage 240 V, (a) Determine the output power and the efficiency. (b) If the brush voltage drop 1.2 V, determine the output power and the efficiency. Jiskan *Do not forget to draw the equivalent circuit first. PhD

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> Q. 6. The nominal power of a shunt generator is 30 kW. The nominal
output
brasistoltage of the generator is 240 V. The shunt field winding
resistance is 50 2. The armature resistance is 0.1 0. The operating point
parameters are given as the rotor emf 255 terminal voltage 240 V,
and the mechanical power loss 1232 W. So,
(a) Determine the output power and the efficiency.
(b) If the brush voltage drop is 1.2 V, determine the output power and the
efficiency.
**Do not forg to draw the equivalent circuit first.
P
rahin Jiskan
an, PhD
Transcribed Image Text:in Pal > Q. 6. The nominal power of a shunt generator is 30 kW. The nominal output brasistoltage of the generator is 240 V. The shunt field winding resistance is 50 2. The armature resistance is 0.1 0. The operating point parameters are given as the rotor emf 255 terminal voltage 240 V, and the mechanical power loss 1232 W. So, (a) Determine the output power and the efficiency. (b) If the brush voltage drop is 1.2 V, determine the output power and the efficiency. **Do not forg to draw the equivalent circuit first. P rahin Jiskan an, PhD
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