For the circuit shown in the following do the following. Find the impedance of the circuit. 150 W * C- 60 p O 15+j 82.17 ohm O 150+j 182.71 ohm O 12+j 12.7 ohm 0 115cos(378t+10) 215+i12.71 ohm 0000 LM 0.6 H
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- Shown in the figure below is an "RL" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 9.84 Volts and is running at a frequency of f = 8.585e+04 Hz. The resistor has a resistance of R = 2170 and the inductor has an inductance of L = 3.54e-03 Henries. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Determine the numerical value of Ztot = 2890.5 Determine the numerical value of $z= = 41 Determine the current through the circuit: • I(PEAK) = 4.81E-3 • I(RMS) = 3.404E-3 Determine the voltage across the resistor: • VR(PEAK) = 7.387 • VR(RMS) = 5.22 ✔✔ Amps ✔Amps Write the FORMULA for the phase of the total impedance of the circuit z... = | tan-1 2701 R x Volts X Volts Determine the voltage across the inductor: • VL(PEAK) = 9.184 • VL(RMS) = 6.49 ✔ Volts Volts L R²+ WL- ✔ degrees 2 If a second circuit were connected in parallel with the inductor, this circuit would be considered as: O a low-pass filter O a capacitive switcher…what is the reactive power absorbed by the load ZL in VAR? Assume source is in rms"If lab is equal to 595.8252306 and lb is 344296, the phase sequence is:" O POSITIVE O NEGATIVE
- The rms value of the resultant current in a wire carries a dc current of 10 A and a sinusoidal alternating current of peak of value 20 A is-For the following parts, identify the name of each circuit, plot the output waveform, and find the DC output average voltage. Part (a) V 1 cycle V₁ = V sin cor Part (b) PE Part (c) Vm Vi ele eeeeeeeeeeeeee D D₂ D₁ D₂ R Va + D₂ D₁can you please give me the comple solution for this question, thanks. A certain voltage function contains a constant term, a fundamental and third harmonic. The maximum value of the fundamental is 85 % of the constant term and the maximum value of the third harmonic is 55 % of the constant term. If the effective value of this function is 180.3V, find the magnitude of the two harmonics. A.IstHarmonic = 75 V , 3rd Harmonic = 120V B. Ist Harmonic = 80 V , 3rd Harmonic = 125V C. IstHarmonic = 120 , 3rd Harmonic = 75V D. Ist Harmonic = 125 V , 3rd Harmonic = 80V E. NOTA
- Shown in the figure below is an "RC" circuit drive by an AC power source. The AC power source has an RMS voltage of Vps (RMS) = 11.58 Volts and is running at a frequency of f = 1.326e+04 Hz. resistor has a resistance of R = 3750 2 and the capacitor has an capacitance of C = 3.17e-09 Farads. Vps R ww Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit tot = Determine the numerical value of Ztot = Determine the numerical value of Pztot= Determine the current through the circuit: • I(PEAK) = • I(RMS) = Determine the voltage across the resistor: Amps Amps S2 C degreesThe peak to peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 9 cm and the 'volts/cm' switch is on 25 V/cm. The peak voltage is given by O 2.78 V O 159.07 V O 112.50 V O 225.00 VIn an experiment, the function generator is adjusted to generate a square voltage at a certain frequency. This voltage is displayed on an oscilloscope and the reading is 10 V peak-to-peak. The rms value of this voltage is .What will be the rms value of this voltage if the frequency is reduced to the half value? 3.536 Vrms . 3.536 Vrms O 5 Vrms . 1.7677 Vrms O 3.536 Vrms. 1.7677 Vrms O 5 Vrms . 5 Vrms ...... O 10 Vrms . 10 Vrms ......
- For the circuit shown below, determine the voltage of the -j10 capacitive reactance. -jsa jl0n 0.5L-90 ILOA(1 -j102 jsn 52 102 AThe peak distance of a sinusoidal waveform displayed on a C.R.O. screen is 6 cm and the 'volts/cm' switch is on 33 V/cm. The peak to peak voltage is given by O 396.00 V O 5.50 V O 139.99 V O 99.00 VThe average value of sinusoidal varying voltage is more than its r.m.s. value. Select one: O True O False Which of the following formula is CORRECT? a. E= - L d0/dt O b. E = - N dl/dt O . L= NI / O O d. W = 0.5 12L In a step down transformer, number of turns in the primary winding is lesser than the number of turns in the secondary winding. Select one: O True O False