For the below shown rectifier configuration, find the expression for the average value of voltage across the load resistor R, if the supply voltage Vs = Vm sinwt and firing angle = a. RLOAD Vm/T Cosa Vm/TT (1+cosa) О 2Vm/п сosa О 2Vm/T (1+cosa) O O O
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- What is CEMF?Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the aboveA single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.
- H.W3 The single-phase full wave controlled rectifier has a R-L load with R= 0.552 and L= 6.5mH. The input voltage V, 220V at 50Hz. The delay angle is a-30, plot the input and output waveforms. Then determine: -The average thyristor current -The rms thyristor current -The output rms current -The average output current - The efficiency NOTE: Drive any formula that used in solutionIn a single phase full wave controlled rectifier connected to Inductive load (with freewheeling diode) find the expression for the average value of voltage across the load when supply voltage is Vs = Vm sinwt and firing angle = a. Vm/TT cosa 2Vm/TT cosa Vm/TT (1+cosa) 2Vm/TT (1+cosa)3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL
- Aasty VIJlc gn, ödljö A dziall jajc D Q4. For the following bridge rectifier circuit, draw the output voltage waveform across the load (RL) showing the maximum value. Calculate the following: The average value of the output voltage across the load (RL). a. b. The rms value of the output voltage across the load (RL). c. The average load current. d. The rms value of the load current. (Use constant voltage drop model for the Silicon diode) 5:1 110 Vrms Assignment1- (ENEL2104) Page 2Power supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V ams 5OHZ İL-DC =05A RL VL-DC =20VV, is a 60Hz source with a peak voltage VP-120V is feeding a rectifier, assume ideal diode. The load resistance has a value of R= 10 k0. If ripple voltage Vr = 2V, the Diode average current Ipavg is VI Select one: a. + e. None Ob. 580mA Oc. 850mA Od 245mA 425mA D C: www tu Vo Q6
- H.W:- For a single phase half wave uncontrolled rectifier if the input supply voltage is (v= 310 sin314t), at frequency (f= 50 Hz). Then determine the followings:- Vm. Vmean- i. Draw the rectifier circuit. un %3D ii. Draw the input and the output voltages waveforms. iii. Determine the mean and rms values of the output voltage. s Ec iv. If the load is (R=10 S), then determine the mean and rms values of the current. 2019Note: Answer All question 1: A) For a single-phase half-wave uncontrolled rectifier with (RL) load, find the rms value of the output voltage (V) and form factor (FF%) with supply voltage: v,(t) = 10 sin(wt). Draw the circuit diagram and sketch the voltages and current waveforms. The conduction angle B = 220°. %3D5-For single phase half-wave controlled rectifier with a freewheeling diode connected across the inductive load, the supply voltage is 220V (RMS). The mean value of the output voltage for a=45 is: 100.7V 70.9V 84.5V 6-For fully controlled single phase bridge rectifier with inductive load (R=102, L=50mH), F=50HZ and a=45', the load current is: Continuous discontinuous verge continuous 7-Fully controlled three phase bridge rectifier circuit is supplied through delta-star transformer. For highly inductive load, the waveform of the line supply current (primary line current of the transformer) is: Square quasi-square six- step