During World War II, B.F Skinner - the noted psychologist-worked for the US Army trying to use pigeons to guide bombs. Pigeons have excellent eyesight, do not get air sick, and Skinner had good success shaping the pigeons to peck at keys in response to their environment. Skinner devised a special bomb with a nosecone for the pigeon to see out of and to guide the flight of the missile to hit its target. Below is the training data of a pigeons in the nosecone of a bomb and the success rate of landing in the correct landing zones. Landing zones were constructed in football fields divided into thirds. The targeted third would rotate with a giant checkerboard used to denote the correct zone. (Chance performance is 1 in 3.) Here are the data: 24 33 36 25 90 32 33 97 38 28 17 16 29 Don't waste time computing your own mean and SD. Use these: The mean is 38.31 The SD is 25.40 A. Hmm, Skiner's pigeon bomb got 38% correct. Is that any good? Maybe this could all be due to: (Write your answer in the box) B. We will use a two-tailed test. 1. Ho: X = Ø 2. H₁: X Ø 3. Ho: μ = Ø 4. H₂: X = μ 5. H₁: X = μ 6. Ho: X = μ Enter the number of the expression indicating the null hypothesis into this box: And enter the number of the expression indicating the alternative hypothesis into this box: C. Calculate a t and enter it into this box (to the second decimal palce)
During World War II, B.F Skinner - the noted psychologist-worked for the US Army trying to use pigeons to guide bombs. Pigeons have excellent eyesight, do not get air sick, and Skinner had good success shaping the pigeons to peck at keys in response to their environment. Skinner devised a special bomb with a nosecone for the pigeon to see out of and to guide the flight of the missile to hit its target. Below is the training data of a pigeons in the nosecone of a bomb and the success rate of landing in the correct landing zones. Landing zones were constructed in football fields divided into thirds. The targeted third would rotate with a giant checkerboard used to denote the correct zone. (Chance performance is 1 in 3.) Here are the data: 24 33 36 25 90 32 33 97 38 28 17 16 29 Don't waste time computing your own mean and SD. Use these: The mean is 38.31 The SD is 25.40 A. Hmm, Skiner's pigeon bomb got 38% correct. Is that any good? Maybe this could all be due to: (Write your answer in the box) B. We will use a two-tailed test. 1. Ho: X = Ø 2. H₁: X Ø 3. Ho: μ = Ø 4. H₂: X = μ 5. H₁: X = μ 6. Ho: X = μ Enter the number of the expression indicating the null hypothesis into this box: And enter the number of the expression indicating the alternative hypothesis into this box: C. Calculate a t and enter it into this box (to the second decimal palce)
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.2: The Least Square Line
Problem 4E
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Transcribed Image Text:X-μ
sd
√n
df = n -1
t =
t =
X-Y
SDx²+ SDy
df = n₁ + n₂-2
n
B. We will use a two-tailed test.
1. Ho: X = Ø
2. H₁: X = Ø
3. Ho: μ = Ø
4. H₂: X = μ
During World War II, B.F Skinner - the noted psychologist-worked for the US Army trying to use pigeons to guide
bombs. Pigeons have excellent eyesight, do not get air sick, and Skinner had good success shaping the pigeons to peck
at keys in response to their environment. Skinner devised a special bomb with a nosecone for the pigeon to see out of
and to guide the flight of the missile to hit its target. Below is the training data of a pigeons in the nosecone of a bomb
and the success rate of landing in the correct landing zones. Landing zones were constructed in football fields divided
into thirds. The targeted third would rotate with a giant checkerboard used to denote the correct zone. (Chance
performance is 1 in 3.)
Here are the data: 24 33 36 25 90 32 33 97 38 28 17 16 29
Don't waste time computing your own mean and SD. Use these:
The mean is 38.31 The SD is 25.40
5. H₁: X = μ
6. Ho: X = μ
A. Hmm, Skiner's pigeon bomb got 38% correct. Is that any good? Maybe this could all be due to:
(Write your answer in the box)
D
SDD
√n
df = n -1
t
=
C. Calculate a t and enter it into this box
Enter the number of the expression indicating the null hypothesis into this box:
D. Enter in the critical value for t:
And enter the number of the expression indicating the alternative hypothesis into this box:
Enter the number of your response into the box:
E. Given the t that you calculated and the critical t, what decision do you make about the null?
1. I would reject the null
2. I would fail to reject the null
3. I would accept the null
4. I would accept the alternative
(to the second decimal palce)
if using the .01 alpha level
F. The difference in the sample to chance is likely due to?
1. An effect
2. Chance
Enter the number of your choice into the box:
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