Show Complete solution step by step. Determine the weight (mass) of steel bars usedfor stirrups needed for the delivery of thespecified material. (Please refer to the figure andinformation below).Use: hook length = 6d; where d = diameter of barSUPPORT@ MIDSPANSUPPORT3- 20mm. diam.2- 20mm. diam3- 20mm. diam2- 20mm. diam2- 20mm. diam3- 20mm. diam3000L/4L/4LONGITUDINAL FLOOR BEAM1:100mm.5 4SCALEREINFORCEMENTSDIMENSIONSВEAMSUPPORTSTOP BARSMIDSPANTOP BARSSTIRRUPSWIDTHHEIGHTвоттом ВARSвоттом BARS2 pe. 20mmo2 pc. 20mmotamm. OSTIRRUPS SPACED2@50 mm 0mmREST 10m ONOCFLOOR LONGTUCNALx 20mmo200300EAM2 pc. 20mmo

Here we use weight per unit length × total length of stirrup bars to determine the total weight of…

Answered: Determine the weight (mass) of steel…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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SITUATION 19: A lapped bolted tension member is shown in figure below. Diameter of hole is 2.5 mm bigger than the diameter of bolt; the diameter of bolts is 22 mm and the plate material is A36 steel Fy = 275 MPa, Fu 415 MPa. Assume the fasteners are adequate and do not control the tensile capacity. 12 50 75 350 75 50 50 100 100 50 50 85. Determine the net area for the tensile capacity of the lapped joint. a. 5,250 mm² b. 1,554 mm² c. 1,554 mm² d. 3,318 mm² 86. What is the maximum allowable shear strength? a. 1,630.950 kN b. 1,254.960 kN c. 1,680.975 kN d. 1,492.98 kN 87. Determine the tensile capacity of the lapped joint based on gross area. a. 693.000 kN b. 202.125 kN c. 252.656 kN d. 866.250 kN
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Question 4 Complete the table below for the steel sections shown. All sections are bending about their horizontal axis. Section Location hep Ney Slenderness (show calculations) of element bf Flange te ld ++ tw be = 800 mm Web tf = 20 mm d = 1440 mm tw = 16 mm Grade 300, heavily 入。= Whole Asp= Asy= welded plates section br Flange tr d Web bf = 800 mm te = 20 mm d = 1420 mm tw = 16 mm Grade 300, heavily welded plates 入。= Whole Asp= Asy= section
An A36 tension member shown in the figure is connected with three 19 mm diamter bolts. Diameter of hole = 22mm. Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm2 y = 50.55 mm Fy = 248 MPa Fu = 400 MPa Determine the design strength due to yielding in the gross section. (kN)
Determine the safe load of the column section shown, if it has a yield strength of 25 MPa. E = 200000 MPa. Use NSCP Specifications. Fyz248 mpa Properties of Channel Section d = 305 mm t₂ = 7.2 mm A = 3929 mm² t₁ = 12.7 mm Ix=53.7 x 10mm¹ x = 117 mm Properties of W 460 x 74 A = 9450 mm² b = 190 mm ly= 1.61 x 10 mm x = 17.7 mm tw = 9.0 mm rx = 188 mm ry = 41.9 mm d = 457 mm tr = 14.5 mm Ix = 333 x 10 mm Iy = 16.6 x 10mm* 7.21 When the height of column is 6 m. When the height of column is 10 m. Assume K= 1.0 457 CIVIL ENGINEERING- STEEL DESIGN

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