Determine the missing values. Express in 3 SF If the number is too big/small, Express the following number in scientific notation. Do NOT include unit in your answer. Please use e to refer to power of 10. For example, 1x 10^6 should be entered as 1e6, 4.5 x 10^-7 should be entered as 4.5e-7. conc. of analyte absorbance (M) molar absorptivity (M-1 cm-4) %T pathlength (cm) 4.35x10 3 21.2 1550 1.55x10 0.167 5.00
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- 50 Percentage Red No. 40 Soln 100% 80% 60% 40% Table 4.1: Dilutions of Red No. 40 & Absorbance Volume of Red No. 40 Soln (mL) 10me 8mL опи 4mL Percentage Red No. 40 Soln 100% 80% 60% 40% 20% Volume of DI Water (mL) OML 2mL LIML M UML 8ML Table 4.2: Dilutions of Red No. 40 & Absorbance Concentration Red No. 40 2. Report the wavelength with the maximum absorbance of Red No. 40 dye. Absorbance 20% 2ML Part A: Making a Calibration Curve for Beer's Law 1. Calculate the concentrations of each of your diluted Red No. 40 solutions and add these to Table 4.2. Show at least one sample calculation in the space below. 0.251 0.192 Total Volume 0.181 0·119 0.060 (mL) 10 mL 10 mL 10 mL 10 mL 10 mLP TrueVision HD blackboard.uob.edu.bh/ultra/courses/ 19902 1/outline/assessment/ 452605 1/overview/e 1768814 1?cou Voitmeter e e salt bridge Fe KCI Cu FeSO4 CUSO,The original solution was diluted by a factor of three, and then the absorbance of the diluted cereal sample solution was measured and recorded as (2.0x10^-1). Use the following trendline and dilution factor to determine the concentration of iron, in unit of M, in the original cereal sample solution. The trendline (linear regression) as displayed on the plot is y = 11898x - 0.0112.
- The concentration of acetylsalicylic acid in an antipyretic tablet was determined by HPLC using a normal calibration curve. Standard solutions of acetylsalicylic acid were prepared and analysed using a 10µL loop. The results obtained for the standards are tabulated below: Conc. of Acetylsalicylic Acid (ppm); Signal (arbitrary units) 50; 6352 100; 12869 150; 19175 200; 25536 250; 31936 To determine the concentration of acetylsalicylic acid in an antipyretic tablet, 10 tablets were weighed (6.500 g total) and crushed to a fine powder using a mortar and pestle. A quantity of powder equal the mass of one tablet was added to a 100 mL volumetric flask. The tablet powder was dissolved with 20 mL of methanol and the flask was made to volume using water. The solution was filtered. A 1.000 ml aliquot was transferred to a 10 ml volumetric flask, which was then made to volume with water. Analysis was conducted using a Bio Sil HL C18, 250mm x 4.6mm column; 5um, with a mobile phase of acetonitrile:…Often the analyst will compare known quantities of analyte to unknown quantities of the material to be analyzed. This may be done in one of three ways: -use calibration curves; use standard additions; or use internal standards. The method of standard additions would be used when A) the quantity of sample analyzed or the instrument response varies from run to run. B) the standard solutions and the unknown solution all have similar characteristics are unaffected by the other material in the sample. C) the sample composition is unknown or complex and affects the analytical signal.A lab pair’s Beer’s Law calibration graph 0.08 < A < 0.79 had a best-fit line of A = 0.013 C – 0.023. Data was: off-scale for both the stock solution and solution #1 (10.00 mL stock diluted to 25.00 mL); solution #2 (1.00 mL stock diluted to 25.00 mL) had A = 0.85, and solution #3 (1.00 mL of solution #1 diluted to 25.00 mL) had A = 0.73. What are the concentrations of solution #3 and the stock solution?
- 1. Use the following Absorbance Data to generate a Bradford Assay Standard Curve. Protein Concentration Absorbance at 595nm (mg/mL) 0.05 Chart Title 0.0092 0.1 0.02 0.2 0.04 0.3 0.112 0.4 0.167 0.5 0.1980 0.6 0.2436 Absorbance at 595nm 0.3 4y = 0.4499x - 0.0254 R? = 0.9824 0.25 0.2 0.15 0.1 0.05 0.1 0.2 0,3 0.4 0,5 0.6 0.7Below are responses generated using the isolated guinea-pig ileum preparation to determine a pA₂ value for the cholinergic antagonist homatropine. Responses are expressed in millimetres +/- SDM (n = 4). Plot the data and then determine by Schild analysis the pA₂ value and Schild slope. So that's TWO drawn graphs to plot on LIN/LOG paper and submit..not EXCEL graphs please. What conclusions can you draw; does the experiment/data fulfil the criteria for a valid Schild analysis? Acetylcholine ACH Alone Concentration ACH + ACH + ACH + Homatropine Homatropine Homatropine 3 x 10-⁹M 1 x 10-M 3 x 10-M [Molar] 3 x 109 3 +/- 1 6 x 109 8 +/- 3 No response 3 x 10-8 28 +/- 6 10 +/- 4 No response 6 x 108 38 +/-8 21 +/-9 5+/-2 No response 3 x 10-7 55 +/- 5 43 +/- 7 27 +/-9 10 +/- 4 6 x 10-7 56 +/- 5 52 +/- 3 38 +/- 7 20 +/-7 3 x 10-6 55 +/-4 53 +/- 6 43 +/- 6 6 x 106 56 +/-2 54 +/- 5Sample IdentificationCodeConcentration of M%TA=2-log(%T)Q50004.00 x 10-417.90.75Q50013.20 x 10-425.00.6Q50022.40 x 10-435.70.46Q50031.60 x 10-450.20.3Q50048.000 x 10-570.80.15SampleIdentificationCode%TA=2-log(%T)AMQ0210150143.70.359518560.360.000192Q0210150244.10.355561410.360.00018Q0210150343.80.358525890.360.00017Q0210150444.10.355561410.360.00018Q0210150543.80.358525890.360.00017What was their percent error?43%Does Batch 021015 meet legal requirements?No, because it is not between 2.85 * 10(4) and 3.15 * 10(4)Well #DropsBluedye1234567891012345678910Drops 9Distilled water876543210Concne 0.26tration0.52Test Tube #0.781.041.3Solutions3Concentration (M)2.082.32.6Concentration (ppm)1:1 dilution11.82Starting Dilution21.562:1 dilution0A.Zero standard0Was your calibration curve as linear as you expected?B.Did you experience any âdriftâ of the resistance readings?C.What is the equation of your best-fit line?D.What commercial drink did you analyze?E.Assuming…
- Please create a caption for this table. Solution NaCl Conc. (%) Osmolality (mOsm) % transmittance Absorbance % hemolysis % crenation C distilled 0 0 0.001029 4.987584625 100 0.03354 1 0.177179111 54.61 0.001551 4.809388202 96.42720001 0.05837 2 0.297126222 91.58 0.01012 3.994819487 80.09527231 0.08444 3 0.442542222 136.4 3.849 1.414652089 28.3634704 0.134 4 0.590164444 181.9 64.8 0.188424994 3.777880643 0.2125 5 0.74752 230.4 95.64 0.019360433 0.388172513 0.3368 6 0.89644 276.3 99.56 0.001915112 0.038397585 0.5336 7 1.095648889 337.7 99.98 8.68676E-05 0.001741676 0.9834 8 1.336711111 412 100 0 0 2.1 9 1.755568889 541.1 100 0 0 7.9 10 2.674395556 824.3 100 0 0 57.83 11 4.490211111 1384 100 0 0 99.72Volume of dye solution added (mL) 9.80 mL Concentration of bleach solution used (M) 0.090 M Volume of bleach solution added (mL) 0,20 mL. Total Volume of solution (mL) 10.0 mL O5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 ABS Ln Abs = -4.860e-2 t + 1.35e-1 0.0 INABS -0.2 -0.4 1/ABS -0.6 -0.8 -1.0 -1.2 -1.4 Time (s) -1.6 b) From the data above, what are the initial molar concentrations of [dye] and [bleach] for your experiment? (NOTE: The concentration of the stock yellow dye solution is 3.40x10 M) [dye)o (M) [bleach]o (M) In Absorbance-3 A 0.3202 (±0.0001) g sample of a pure monoprotic acid required 20.04 (±0.02) cm° of 0.1005 (±0.0005) mol dm neutralisation. Find the molar mass of the acid in g mol together with its uncertainty also in g mol, with an appropriate number of digits. NaOH for -1 Select one: a. 1.59 x 102+ 0.2 g mol b. 1.60 x 10 + 0.03 g mol C. 1.590 x 102 + 0.03 g mol d. 1.590 x 10- + 0.2 g mol 1.60 x 10-+0.2 g mol е. Clear my choice