Data are given in the following table for completely reversed strain-controlled fatigue tests on RQC-100 steel. The elastic modulus is E= 200 GPa. Determine constants for the strain-life curve. Ga, MPa Epa Ng. cycles 0.0202 0.0100 631 574 0.01695 227 0.00705 1 030 0.0045 505 0.00193 6450 0.0030 472 0.00064 22 250 0.0023 455 (0.00010) 110000

Data are given in the following table for completely reversed strain-controlled fatigue tests on RQC-100 steel. The elastic modulus is E= 200 GPa. Determine constants for the strain-life curve. Ga, MPa Epa Ng. cycles 0.0202 0.0100 631 574 0.01695 227 0.00705 1 030 0.0045 505 0.00193 6450 0.0030 472 0.00064 22 250 0.0023 455 (0.00010) 110000

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.5P: The results of a tensile test are shown in Table 1.5.2. The test was performed on a metal specimen...

See similar textbooks

Similar questions

The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
An applied torque results in a shear strain (y) of 3.75 x 103 in a solid circular steel shaft. At this strain, a portion of the shaft cross- section yields as shown in Figure 2. Determine the magnitude of the applied torque. Take G = 80 GPa and yy = 2.8125 x %3D 10-3 FIGURE 2: Plastic zone 50 mm 200 mm Elastic core
A steel specimen of 300 mm length and 30 mm diameter is subjected to tensile test in a computerizedUTM. Under 54 kN of tensile load, the final length and diameter are observed as 300.112 mm and29.99634 mm respectively. Calculate (a) the Poission’s ratio and (b) the values of three moduli.
2. A steel bar, whose cross section is 0.55 inch by 4.05 inches, was tested in tension. An axial load of P = 30,500 lb. produced a deformation of 0.105 inch over a gauge length of 2.05 inches and a decrease of 0.0075 inch in the 0.55-inch thickness of the bar. * Determine the lateral strain. Your answer Determine the axial strain. Your answer Determine the Poisson's rati v. Your answer Determine the decrease in the 4.05-in. cross-sectional dimension (in inches). * Your answer
In a standard tensile test, an aluminum rod of 20-mm diameter is subjected to a tension force of P = 30 kN. Knowing that E = 70 GPa, and the change in diameter of the rod= 0.00955 mm, determine the poissons' ratio v. -20-mm diameter gage length=150 mm
1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 ܩܙ ܘ 5.5 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106
The following observations were made during a tensile test on a mild steel specimen 40 mm in diameter and 200 mm long. Elongation with 40 KN load (within limit of proportionality) Change in length=0.0202 mm. Determine stress and strain value
PROBLEMS 203. During a stress-strain test, the unit deformation at a stress of 5000 psi Wap ODserved to be 0.000167 in./in. and at a stress of 20,000 psi it was 0.000667 in./in. If the proportional limit is 30,000 psi, what is the modulus of elasticity? What is the stress corresponding to a strain of 0.0002 in./in.? Would these re- sults be valid if the proportional limit were 18,000 psi? Explain. E = 30 X 106 psi; S 6000 psi %3D Ans. 204. A uniform bar of length L, cross-sectional area A, and weight W is sus- WL If pended vertically from one end. Show that its total elongation is & = 2AE wL? its weight per unit volume is w, show also that & 2E A steel rod having a cross-sectional area of sq in. and a length of 600 ft is suspended vertically. It supports a load of 5000 lb at the lower end. If steel 30 X 106 psi, find the total elongation in the rod. Ans. 8 = 2.64 in. 205 weighs 490 lb/cu ft and E Hint: Use the result of Prob. 204. steel wire 30 ft long, hanging vertically, supports a…
A steel bar, whose cross section is 0.60 inch by 4.10 inches, was tested in tension. An axial load of P = 31,025 lb. produced a deformation of 0.115 inch over a gauge length of 2.10 inches and a decrease of 0.0080 inch in the 0.60-inch thickness of the bar. a. Determine the lateral strain. b. Determine the axial strain. c. Determine the Poisson’s ratio v. d. Determine the decrease in the 4.05-in. cross-sectional dimension (in inches).
1.14 The stress-strain relation shown in Figure P1.14 was obtained during the ten- sile test of an aluminum alloy specimen. 60,000 40,000 20,000 0.002 0.004 0.006 0.008 Strain, in./in. FIGURE P1.14 Determine the following: a. Young's modulus within the linear portion b. Tangent modulus at a stress of 45,000 psi c. Yield stress using an offset of 0.002 strain d. If the yield stress in part c is considered failure stress, what is the maximum working stress to be applied to this material if a factor of safety of 1.5 is used? Stress, psi
3. A new material is being developed and tested in the lab. The column was made using the new material and was loaded to a constant axial stress of 25 MPa. The deformation is monitored over time according to the following table. The deformation is measured over a length of 250 mm. First sketch strain-time curve and describe the model. Second, determine the elastic modulus and the viscose coefficient. Time (days) Stress (MPa) Deformation (mm) 25 0.6250 1 25 0.6281 25 0.6313 3. 25 0.6344 7 25 0.6469 28 25 0.7125 180 25 1.1875 365 25 1.7656
The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross-section of 0.2 in.? in area and a gage length (the length over which the elongation is measured) of 2.000 inches. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress.