d = -1 The region R is bounded by the x-axis, y-axis, and the line in the graph and has a constant density. To find the centroid of the region you would compute S SR dA = Så fa(®) dydx, få fa(z) x dydx, and rq(x) p(x) p(x) 1(x) Sy dyda where p(x) p(x) q(x) Så falz) dydx 1(x) p(x) = 1/0 = -1 = få fa(z) x dydx Jp(x) Så Sa fal y dydx p(x) 1,0 = = R

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
ChapterA: Appendix
SectionA.2: Geometric Constructions
Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...
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Related questions
Question
-1
110
=
-1
The region R is bounded by the x-axis, y-axis, and the
line in the graph and has a constant density. To find the
centroid of the region you would compute
S SR dA= Sd fa(²) dydx, få fax dydx, and
•q(x)
p(x)
p(x)
Sd Salz) y dydx where
q(x)
Jp(x)
=
d
p(x)
q(x)
•q(x)
fd f(x) dydx
fa(z) x dydx
Sd
p(x)
•q(x)
fdf) y dydx
p(x)
=
=
R
=
Transcribed Image Text:-1 110 = -1 The region R is bounded by the x-axis, y-axis, and the line in the graph and has a constant density. To find the centroid of the region you would compute S SR dA= Sd fa(²) dydx, få fax dydx, and •q(x) p(x) p(x) Sd Salz) y dydx where q(x) Jp(x) = d p(x) q(x) •q(x) fd f(x) dydx fa(z) x dydx Sd p(x) •q(x) fdf) y dydx p(x) = = R =
d
The region R is bounded by the x-axis, y-axis, and the
line in the graph and has a constant density. To find the
centroid of the region you would compute
rd
S SRdA = Sd fa(z) dydx, fd (2) x dydx, and
Jp(x)
p(x)
fdf) y dydx where
pq (x)
Jp(x)
-
IS
-1
Y
1
=
140
p(x)
q(x)
få falz) dydx
Jp(x)
Sd fa(z) x dydx
Sd f(x) y dydx
=
T
=
=
and finally the centroid is
=
R
Transcribed Image Text:d The region R is bounded by the x-axis, y-axis, and the line in the graph and has a constant density. To find the centroid of the region you would compute rd S SRdA = Sd fa(z) dydx, fd (2) x dydx, and Jp(x) p(x) fdf) y dydx where pq (x) Jp(x) - IS -1 Y 1 = 140 p(x) q(x) få falz) dydx Jp(x) Sd fa(z) x dydx Sd f(x) y dydx = T = = and finally the centroid is = R
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