Consider the curve parametrized by x = t4 + 1 and y = tº + 4t5. a) Find dy dx da in terms of t. 3/2t^2+5t Correct. Good Job! d'y b) Find in terms of t. dx² d²y/dx² = (3t+5)/(4t^3) Correct. Good Job! 33 Preview = 1² + 5t d²y/dx² = Preview 3t+5 4t3 c) For what intervals of this the curve concave up? Enter your answer as intervals separated by a comma.

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