Consider the CRT. If the potential between the two plates is 15, 000 V and the plate separation is L = 2.0 cm, what is the electric field in this region? Assume the electric field is constant in the accelerator?
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Consider the CRT. If the potential between the two plates is 15, 000 V and the plate
separation is L = 2.0 cm, what is the electric field in this region? Assume the electric field is
constant in the accelerator?
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- A uniform electric field is created by two horizontal parallel plate electrodes of length 10 cm separated by a vertical distance d = 5 cm and held at a potential difference V = 250V. A beam of electrons is introduced between the two plates with a horizontal velocity v = 5 x 106 m/s. What is the deflection distance towards the positive plate when the electron beam leaves the electric field? Select one: а. 5.0 cm O b. 3.5 cm С. 1.76 cm d. 8.8 mmf a proton and electron are released when they are 2.0 m apart, find the initial acceleration of electron (in m/s2). The answer (in fundamental SI unit) is ___________ (type the numeric value only)Question 1 a) In J. J. Thomson experiment (1897), an electron moving horizontally with a constant speed vo enters in between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d, is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge to mass ratio, i.e. e/m to be 2v,Y/CEL). (Recall that Thomson received Nobel Prize for his achievement.) b) Calculate e/m, knowing the following data. E=1.6x10* Newton/Coulomb, L=10 cm, Y=2.9 cm, v=2.19x10* km/s. (Be careful to use coherent units.)
- A particle with a charge of -2.00nC and a mass of 0.25 kg is released from a negative plate towards a positive plate. The plates are separated by a 3cm gap. The electric field of the plates if 8x10^6 N/C. Calculate the speed of the charge before the particle hits the positive plate (ignore gravity).Certain sharks can detect an electric field as weak as 1.0 μV/mμV/m. To grasp how weak this field is, if you wanted to produce it between two parallel metal plates by connecting an ordinary 1.5 VV AA battery across these plates, how far apart would the plates have to be? Express your answer in meters.Problem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation is 4.7 mm and the the electric field inside is 26 N/C. An electron is positioned halfway between the plates and is given some initial velocity, v₁. Randomized Variables d=4.7 mm E = 26 N/C Vi,a + + + + + + + + Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? d
- An electron is acceleraled from rest through a potential difference of 3750 V. It enters a region where B = 4.0 × 10-3T perpendicular to its velocity. Calculate, the Radius of the path it will follow. Solve and show the solution. Ans. 5.2 cmTwo large parallel plates are placed horizontally with respect to each other and are then connected to a 200V battery. If the distance beteeen the plates is 2cm, the uniform electric field between the plates is 10^4N/C in the upward direction. If the electron is released from rest at the upper plate, calculate: a) the kinetic energy of the electron after traveling 2cm to the lower plate. b) the time required for the electron to travel this distance.An electron with kinetic energy K is traveling along the positive x-axis, which is along the axis of a cathode‑ray tube, as shown in the figure. There is an electric field E=18.0×104 N/C pointed in the positive y-direction between the deflection plates, which are 0.0600 m long and are separated by 0.0200 m. Determine the minimum kinetic energy ?minKmin the electron can have and still avoid colliding with one of the plates.
- The uniform electric field between two charged parallel plates has a magnitude of 4400 V/m (note that 1 V/m = 1 N/C). If the plates are separated by 0.0100 m and an electron is released from the far negative side of the gap, what will the electron's kinetic energy (in eV) and speed be when it just reaches the positive plate? Note that the electron charge = -1.602 x 10-19 C and the electron mass = 9.11 x 10-31 kg. KE V= ev m/sSituation: The X-ray tubes that generate X-rays contain an electron source separated by about 10 cm from a metallic target. The electrons accelerate from the source to the target by a uniform electric field with a magnitude of about 100, 000 N/C. (a) Compute the potential difference between the electron source and the metallic target. (b) Calculate the kinetic energy of the electrons when they reach the target, assuming that the electrons start from rest.A uniform electric field is created by two horizontal parallel plate electrodes of length 10 cm separated by a vertical distance d = 5 cm and held at a potential difference V = 250V. A beam of electrons is introduced between the two plates with a horizontal velocity v = 5 x 106 m/s. What is the deflection distance towards the positive plate when the electron beam leaves the electric field?