Calcium Chloride (CaCl2) freely dissolves in water by the following equation. CaCl2 (s) Ca²+ (aq) + 2 CF (aq) If 50.0 mL of a 1.00 M solution of CaCl2 (Solution A) is mixed with 105.0 mL of pure water to produce solution B and then 58.5 mL of solution B is mixed with 23.0 mL of solution A to give solution C, what is the concentration of CF (aq) in the final solution? (Solution C) Concentration of CI (aq)

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Chapter4: Chemical Reactions
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Calcium Chloride (CaCl2) freely dissolves in water by the following equation.
CaCl2 (s) Ca2+ (aq) + 2 C (aq)
->
If 50.0 mL of a 1.00 M solution of CaCl2 (Solution A) is mixed with 105.0 mL of
pure water to produce solution B and then 58.5 mL of solution B is mixed with
23.0 mL of solution A to give solution C, what is the concentration of CF (ag) in
the final solution? (Solution C)
Concentration of CF(aq)
Transcribed Image Text:Calcium Chloride (CaCl2) freely dissolves in water by the following equation. CaCl2 (s) Ca2+ (aq) + 2 C (aq) -> If 50.0 mL of a 1.00 M solution of CaCl2 (Solution A) is mixed with 105.0 mL of pure water to produce solution B and then 58.5 mL of solution B is mixed with 23.0 mL of solution A to give solution C, what is the concentration of CF (ag) in the final solution? (Solution C) Concentration of CF(aq)
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