B. N C. FB = 600 N 2 m 3.5 m 0.5 m A = Fc 450 N 1.5 m 1 m 0.5 m 1.5 m x y

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Add a third cable to this diagram originating at point A and extending up to the wall that B and C are anchored on. This new point, D, is located 1.5 m up from the xy plane and 1 m to the left of the xz plane (point D lies on the same plane as B and C but in between them).  This third cable has a tension of 200N.

Then, determine the resultant force at A: 1) create position vectors for ABAC, and AD, 2) create force vectors along these three position vectors, 3) Determine the resultant force in Cartesian vector notation & 4) Calculate the magnitude and coordinate direction angles of this resultant force.

 

B.
N
C.
FB = 600 N
2 m
3.5 m
0.5 m
A
=
Fc 450 N
1.5 m
1 m
0.5 m
1.5 m
x
y
Transcribed Image Text:B. N C. FB = 600 N 2 m 3.5 m 0.5 m A = Fc 450 N 1.5 m 1 m 0.5 m 1.5 m x y
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