Answered: b. 0.001 M CH3CH2NH2 (Kb = 4.3 x 104)…

b. 0.001 M CH3CH2NH2 (Kb = 4.3 x 104) i. Write the dissociation reaction. ii. Write the Kb expression. iii. Determine the [OH¯] at equilibrium. iv. Calculate the pOH. v. Calculate the pH. %3D

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter17: Spontaneity, Entropy, And Free Energy

Section: Chapter Questions

Problem 100CWP

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