All the following are methods used in.18 *: probability samples except one a. Simple random sampling O b. Systematic sampling c. Stratified sampling O d. Snow ball sampling O
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- What is the difference between a random sample and a composite sample? When would each be used?When a sample presents some matrix interference, which of the ff. are carried out? Dilute sample to minimize sample interference. Prepare a standard addition curve. If possible, remove interference prior to the quantification. Dilute sample until interference is completely removed.First image contains the respective absorbance readings of the samples specified in the 96-well plate set-up in the 2nd image . The absorbance reading that needed to be write should be the average absorbance of 12 - replicate analysis (i.e. Calculate the average of the absorbance of A1 to A12 to get the final absorbance of the "blank".
- Bradford Assay Fill in the average A595 and A595 of sample minus A595 of blank. Show some sample computation. Concentration (micrograms/ml) A595 - trial 1 A595 - trial 2 A595 - trial 3 average A595 A595 of sample minus A595 of blank 0 1.501 1.446 1.447 2 1.624 1.558 1.559 5 1.731 1.749 1.712 10 1.901 1.838 1.892 15 2.161 2.108 2.228 18 2.231 2.277 2.3191mL Stock #1 1mL 2000060 9mL #2 9mL wwwww #3 4. 1mL 0000000 A 9mL wooooo #4 0.1m/L O 1mL 5000000 B 9mL #5 1mL 1mL 9mL wwwwww #6 0.1mL 1mk O. D Using the picture serial dilution scheme and the following information (plate A has 276 colonies, plate B has 298, plate C has 2, and plate D has 30), calculate the average number of colony forming units per mL in the stock tube. Make sure to only use countable plates. Round your answer to the nearest one. Write only the number with any needed commas or decimals. Do not include units.Please discuss the value of international normalized ratio (INR) as a test. Why do you think this is more reliable that the ordinary PT.
- Using Bradford Assay, plot the standard curve and find the unknowns. Protein Concentration A595 of sample 0 0 3 0.220 6.5 0.383 12 0.667 18.8 0.930 24.2 1.090 Unknown 1 1.085 Unknown 2 0.708 Unknown 3 0.193Can you perform spectrophotometric analysis without the following?a. Bradford dyeb. Molecular standardsJustify your answer.The replicate results (mg/L) obtained from calcium determination of a blood sample using atomic absorption spectrophotometry (AAS) and a new colorimetric method were as following: AAS : 11.2, 11.2, 10.6, 11.2, 9.7 and 10.0 Colorimetric : 9.2, 10.5, 9.7, 11.5, 11.6, 9.3, 10.1 and 11.2 Determine whether the mean of both methods have a significant difference at 95% confidence level.
- Make a Chi square using the average calculated from the trials and interpret the results from the data and graph in the attached images. Expected Number: 41) Dosage calculation with same units of measure. EX: MD orders 1000mg Ancef. You have available 2000mg in 10mls. How many mls you give?You also obtained the MIC for a variety of common antifungals by testing them against a single strain of Aspergillus fumigatis. Six replicates of each were tested. MIC (ug/mL) Amphotericin B 1 Miconazole 0.06 Ciclopirox 0.01 Nystatin 0.625 New product 0.1 Two-way ANOVA Amp v. New 3.70E-04 Nys v. New 4.16E-05 Mico v. New 0.04 Cic vs. New 1.50E-05 Additionally, Candida aurus is a fungus that is rapidly becoming resistant to multiple antifungals. Because strains now exist that are completely resistant to three or more families of antifungals, there is room in the market for an antifungal that is effective against C. aurus. If the data above is representative for the efficacy against both A. fumigatus, a fungus that is plentiful and sensitive to most antifungals, and C. aurus, determine whether this efficacy data supports room for this product on the existing marketplace. If you think more data is required in order to make a final decision about this…
