A)A lecturer claims that their course is not too easy and that on average, students score 60%. We want to verify this claim by performing a single tailed test with the null hypothesis μ=60% vs the hypothesis μ>60%. For this, we take a random sample of 50 students. Decide on the appropriate test statistic and compute the corresponding (positive) bound of the critical region for a single tailed test at the 98% level. B)Consider again the example of the lecturer from above. We obtained a sample of 50 students with a mean of μ=61.3% and a sample standard deviation of 18.3% (percentage points, not percentages of μ!) What is the p-value (060%? Give your answer to 3 decimal places.
A)A lecturer claims that their course is not too easy and that on average, students score 60%. We want to verify this claim by performing a single tailed test with the null hypothesis μ=60% vs the hypothesis μ>60%. For this, we take a random sample of 50 students.
Decide on the appropriate test statistic and compute the corresponding (positive) bound of the critical region for a single tailed test at the 98% level.
B)Consider again the example of the lecturer from above. We obtained a sample of 50 students with a mean of μ=61.3% and a sample standard deviation of 18.3% (percentage points, not percentages of μ!) What is the p-value (0<p<1) for this right-tailed test for the null hypothesis μ=60% vs the alternative hypothesis μ>60%? Give your answer to 3 decimal places.
Step by step
Solved in 3 steps
