A hypothetical speed distribution of gas molecules is defined as follows: P(v) = 0 for 0≤v < vo P(v) = 0.21 for vo ≤ v << 2vo P(v) = 0 for 2v0 < v where P(v) is the probability distribution as a function of speed, v. a) Use the normalisation condition to find the value of v. b) What percentage of the gas molecules has its speed between vo and/vo? c) What percentage of the gas molecules has its speed between 0 and 2 ?
A hypothetical speed distribution of gas molecules is defined as follows: P(v) = 0 for 0≤v < vo P(v) = 0.21 for vo ≤ v << 2vo P(v) = 0 for 2v0 < v where P(v) is the probability distribution as a function of speed, v. a) Use the normalisation condition to find the value of v. b) What percentage of the gas molecules has its speed between vo and/vo? c) What percentage of the gas molecules has its speed between 0 and 2 ?
Related questions
Question
Transcribed Image Text:A hypothetical speed distribution of gas molecules is defined as follows:
P(v) = 0 for 0≤v < vo
P(v) = 0.21 for vo ≤ v << 2vo
P(v) = 0 for 2v0 < v
where P(v) is the probability distribution as a function of speed, v.
a)
Use the normalisation condition to find the value of v.
b)
What percentage of the gas molecules has its speed between vo and/vo?
c)
What percentage of the gas molecules has its speed between 0 and 2 ?
Transcribed Image Text:A hypothetical speed distribution of gas molecules is defined as follows:
P(v) = 0 for 0≤v < vo
P(v) = 0.21 for vo ≤ v << 2vo
P(v) = 0 for 2v0 < v
where P(v) is the probability distribution as a function of speed, v.
a)
Use the normalisation condition to find the value of v.
b)
What percentage of the gas molecules has its speed between vo and/vo?
c)
What percentage of the gas molecules has its speed between 0 and 2 ?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 2 images
