A block with a mass of m rests on a frictionless surface and is subject to twoyforces acting on it. The first force is directed in the negative x-direction. The second acts on thebody at an angle e measured from horizontal, as shown. If necessary, use Fs and Fk for the forces ofstatic and kinetic friction.x-mPlease use the interactive area below to draw the Free Body Diagram for this block, assuming it is in static equilibrium.1 Add ForceO Reset AllF1 v 180 vxF2 v 315 vFg v 270 vx: FnFn v 90 vFs v0F1Fs: FgF2Ftotal.x: + (pos)Ftotal,y: - (neg)The surface is frictionless. Please think about whether frictional forces should beconsidered here.It looks like there is at least one force that is expected in the drawing, but isn't inthe right direction.

A block with a mass of m rests on a frictionless surface and is subject to two orces acting on it. The first force is directed in the negative x-direction. The second acts on the ody at an angle 6 measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of tatic and kinetic friction.

A block with a mass of m rests on a frictionless surface and is subject to two orces acting on it. The first force is directed in the negative x-direction. The second acts on the ody at an angle 6 measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of tatic and kinetic friction.

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter5: Newton's Law Of Motion

Section: Chapter Questions

Problem 85AP: Two boxes, A and B, are at rest Box A is on level ground, while box B rests on an inclined plane...

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Problem A sold uniform ball with mass mand dlameter dis supported against a vertical frictioniess wall by a thin massiess wire of length L. a) Find the tension in the wire. m Solution a) Let us first derive the expression for the tension. By Newton's First LN IF the componenes of force that makes this so is Simplifying this results to T- Analyaing the figure above, we arrive at 2. By substitution, we arrive at the following T- sarti if the ball has a mass of 45 kg and diameter 32 cm, while the wire has a length of 30 cm. The tension is equal to T- 0.370 N
Problem 1: A block with a mass of m rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction. The second acts on the body at an angle 0 measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of static and kinetic friction. L. F Please use the interactive area below to draw the Free Body Diagram for this block, assuming it is in static equilibrium. FBD : Fn, F1, Fg, F2, Fs, Fk, a, v 45, 0, 90, 135, 180, 225, 270, 315, 0 Force Labels: Angle Labels: m.
Problem 5: Ablock with a mass of m rests on a frictionless surface and is subject to two forces acting on it. The first force is directed in the negative x-direction. The second acts on the body at an angle e measured from horizontal, as shown. If necessary, use Fs and Fk for the forces of static and kinetic friction. F m -F, Please use the interactive area below to draw the Free Body Diagram for this block, assuming it is in static equilibrium. 1 Add Force O Reset All m. Ftotal,x: Ftotal,y:
anwer should fit the the blanks: Momo with mass m is sliding down an inclined plane that makes an angle Φ relative to the horizontal. The coefficient of kinetic friction between Momo and the inclined plane is μk. Obtain an expression for Momo's acceleration along the incline. Assign a rotated Cartesian plane so that the acceleration is along the positive x-axis and the normal force is along the positive y-axis. The component of the weight parallel to Momo's acceleration is wx = mgBlank 1Φ. The magnitude of the frictional force is f = μkBlank 2. The normal force on Momo is n = mgBlank 3Φ. With these expressions and applying Newton's second law, we arrive at an expression for Momo's acceleration: a = Blank 4 ( Blank 5 - μkBlank 6 )
Assuming that P = 50N, answer the following subproblems 1) What is the limiting value of frictional force between the package and the horizontal platform?2) What is the distance to the left of corner C where the line of action of the normal force crosses base CD of the package?3) Determine whether the package is moving, not moving, only impending to tip or only impending to slide.
The diagram below shows an object of mass m= 20kg being acted upon by a force F=50N at an angle of θ=30o. The coefficient of kinetic friction between the object and the surface is 0.100. a.Draw a Free Body diagram for the object. Be sure to show all forces as well as the reference x,y axis. and Using Newton’s 2nd law, write the force equations for both the x and the y directions. Write these equations in terms of the letters m, F, θ, FN, g, f (little f stands for the friction force). X-direction: _______________________________________________________________ Y-direction:________________________________________________________________ b.Solve for the Normal Force c .Use your answer from part b to find the frictional force. d .Solve for the acceleration of the object. e.If this object was originally moving at 4 m/s, how fast would it be moving after 8 seconds? f .How far will…
hi please draw clear fbd of the above conditon , show all the forces clearly . state each force clearly . i will rate if you provide clear figure
Four forces act on a particle that is in equilibrium where F3 and P are in the xz-plane. The magnitude of one force is know to be P=600 N A) Write the equilibrium equation for the forces in the x- direction. Express your answer in terms of F1,F2,F3, and P. Express know forces in N and angles in degrees B) Write the equilibrium equation for the foces in the y-direction. Express your answer in terms of F1,F2,F3, and P. Express know forces in N and angles in degrees C) Write the equation for forces in the z-direction. Express your answer in terms of F1,F2,F3, and P. Express know forces in N and angles in degrees
he FBD of the block should have looked like this. 1. A contestant in a winter sporting event pushes a block of ice of mass m across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μs, and the coefficient of kinetic friction is μk. θ is the angle the force makes with the x-axis. In this part, we are going to set-up Newton's second Law equations for the cases(1) when the ice block just starts moving, and(2) when it is accelerating to the right with an acceleration a. All answers are symbolic. ALL ANSWERS ARE CASE-SENSITIVE. Subpart 1: Newton's Second Law along the y-axis (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and θ. In both scenarios, there is no acceleration along the y-direction, therefore, ay=0.…
A block is resting on a wooden plank. There is a hinge on one end of the plank which allows the other end to be lifted to create an angle, θ, with respect to the horizontal as shown in the figure. The coefficient of static friction between the block and the plank is μs. Please use the interactive area below to draw the Free Body Diagram for the block. Use Fs to denote the force of static friction. The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs. If a student measures that the block begins to move at an angle of θ = 25°, what is the numerical value of the coefficient of static friction, μs?
Use the worked example above to help you solve this problem. An Eskimo returning from a successful fishing trip pulls a sled loaded with salmon. The total mass of the sled and salmon is 50.0 kg, and the Eskimo exerts a force on the sled by pulling on the rope. Suppose the coefficient of kinetic friction between the loaded sled and snow is 0.200. (a) The Eskimo pulls the sled 5.60 m, exerting a force of 1.10 x 102 N at an angle of 0 = 0°. Find the work done on the sled by friction, and the net work. J W fric W net (b) Repeat the calculation if the applied force is exerted at an angle of 0 = 30.0° with the horizontal. W fric W net
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