A 50.00 mL sample of white dinner wine required 28.54 mL of 0.03867 N NaOH to achieve a phenolphthalein endpoint. Express the acidity of the wine in terms of %w/v of tartaric acid (H2C4H4O6, MW=150.09g/mol).
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A 50.00 mL sample of white dinner wine required 28.54 mL of 0.03867 N NaOH to achieve a phenolphthalein endpoint. Express the acidity of the wine in terms of %w/v of tartaric acid (H2C4H4O6, MW=150.09g/mol).
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- How many ml of 0.05 N HC2 H3O2 (acetic acid) and how many ml of 0.05 N H2SO4 would be neutralized by 10 ml of 0.5 N NaOH?Write the values of Y and X. H2SO4 CH3CH=CH2 + H2O CH;CH-CH2 H HỌ 2-propanol an alcohol The pKa of a protonated alcohol is about -2.5, and the pKa of an alcohol is about 15. Therefore, as long as the pH of the solution is greater than Y and less than X, more than 50% of 2-propanol will be in its neutral, nonprotonated form. Express your answers using two significant figures separated by a comma. AX中 Y, X = %3|A mixture contains Na2CO3, NaOH and inert matter. A sample weighing 1.500 g requires 28.85 ml of 0.5000N HCl to reach the a phenolphthalein endpoint and an additional 23.85 ml to reach the methyl orange end point. What are the percentages Na2CO3 and NaOH?
- A 50.00-mL sample of a white dinner wine required 25.87 mL of 0.03291 M NaOH to achieve a phenolphthalein endpoint. Express the acidity of the wine in grams of tartaric acid (H2C4H4O6; 150.09 g/mol) per 100 mL.Use the modified H-H shown below to calculate the blood plasma pH under the following conditions: [HCO3-] = 0.022 M and pCO₂ = 46 mmHg. Provide your answer to two decimal places. Do not enter units. Dissociation Constant pH = 6.1 Bicarbonate (mmol/L) HCO 0.03 x PCO₂ CO₂ Solubility Constant CO₂ Partial Pressure (mmHg)A solution contains formic and tartaric acids. A 25.00 mL aliquot portion is treated with 50.00 mL of a 0.1663 mol/L solution of cerium(IV) in 12 molL sulfuric acid; after boiling for one hour, it is cooled to room temperature and the excess cerium(IV) is titrated with 8.24 mL of iron(ll) 0.1108 molL. Under these conditions all organic acids are oxidized to carbon dioxide. Another 25.00 mL aliquot portion of the acid solution is treated with 20.00 mL of 0.2383 molL cerium(IV) in 4 molL perchloric acid and heated at 50°C for 20 minutes. The solution was then titrated with 14.65 mL of 0.1012 mol/L oxalic acid. Under these conditions all organic acids are oxidized to formic acid. (a) Calculate the concentration of formic acid in g/L (b) Calculate the concentration of tartaric acid in g/L
- The disinfectant phenol, C₆H₅OH, has a pKₐ of 10.0 in wa-ter, but 14.4 in methanol. (a) Why are the values different? (b) Is methanol is a stronger or weaker base than water? (c) Write the dissociation reaction of phenol in methanol. (d) Write an expres-sion for the autoionization constant of methanol.Calculate the pOH of a solution of methylamine and lye. Initially, [CH3NH2] = 1M and [NaOH] = 0.02M. CH3NH2(aq) + H2O(l) ↔ CH3NH3+(aq) + OH-(aq) Kb = 4.38x10-4 NaOH(aq) → Na+(aq) + OH-(aq) Strong base a. 1.70 b. 1.39 c. 1.68 d. 4.12 e. 2.33The amount of tartaric acid is responsible for the tartness of wine and controls the acidity of the wine. Tartaric acid also plays a very significant role in the overall taste, feel and color of a wine. Tartaric acid is a diprotic organic acid The chemical formula for tartaric acid is C4H6O6 and its structural formula is HO2CCH(OH)CH(OH)CO2H. A 50.00 mL sample of a white dinner wine required 21.48 mL of 0.03776 M NaOH to achieve a faint pink color. Express the acidity of the wine in terms of grams of tartaric acid, H2C4H4O6 (M. M. = 150.10) per 100 mL of wine. Assume that the two acidic hydrogens are titrated at the end point. MM H2C4H4O6 = 150.10 MM NaOH = 40.00 Below is the balanced chemical equation for this titration.
- (a) Find the pH of a 1.00 L solution prepared with 12.43 g of base (CH2OH)3CNH2 (MW =121.135 g/mol) plus 4.67 g of its conjugate acid (CH2OH)3CNH3Cl (MW = 157.596 g/mol).(b) How many mL of 0.500 M NaOH should be added to 10.0 g of (CH2OH)3CNH3Cl to give a pH of 7.60in a final volume of 250 mLConsider the pKa of (CH2OH)3CNH3+ = 8.072Each row represents an experimental “run” (in this case, averaged sample of mango wine). Column A shows the run number; Column B shows the percentage of ethanol; Column C shows the amount of glycerol (in g/L); Column D shows the amount of acid (in g/L); Column E shows the temperature of the run (in °C); and Column F shows the pH of the run. Y represents Ethanol of mango wine. 1. Create a scatterplot of the ethanol data for all 20 runs a. Draw a graphical representation of the model that you chose to use. b. Comparing the model to your data, evaluate its fit in one or two sentences. (Not sure what this question is getting at. I've provided all the information given) c. Replace the generic Yi = β0 + ε with the information you have here. Please help. I have no idea what this even means or where to start. HERE is the attached dataset to start with; a b c d e f Run Ethanol Glycerol Acidity Temp pH 1 4.8 3.5 0.84 24 3.8 2 9.6…5. a) The Kw value that we normally use is for room temperature (25°C). Calculate the equilibrium H+ concentration and pH of pure, neutral water at 0.0°C (Kw= 1.14 x 10-15at 0.0°C) b) Methylamine (CH3NH2) is a derivative of the weak base ammonia. Write the equation for the ionization of methylamine in water, and use the I.C.E. method to find the pH of a 3.75 M CH3NH2 solution.(Kb= 4.37 x 10-4at 25°C)