7. The following data were collected for the reaction: (CH3);CBr + OH¯ (CH3);COH + Br- rate of reaction (mol L-' s-') [(CH).CBr] 0.50 M trial [OH] 1 0.050 M 0.0056 1.00 M 0.050 M 0.011 3 1.00 M 0.10 M 0.011 4 1.50 M 0.050 M 0.017 Determine the form of the rate law and calculate k, the rate constant. You must include units with your answer! Feel free to use any snace above to determine relative concentrations/rate but it's not required
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
![7. The following data were collected for the reaction: (CH;);CBr + OH-
(CH),СОН + Вr-
trial
[(CH;) CBr]
[OH]
rate of reaction (mol L-' s-')
1
0.50 M
0.050 M
0.0056
1.00 M
0.050 M
0.011
3
1.00 M
0.10 M
0.011
4
1.50 M
0.050 M
0.017
Determine the form of the rate law and calculate k, the rate constant. You must include units with your
answer! Feel free to use any space above to determine relative concentrations/rate, but it's not required.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F38e4eb1d-f814-44b2-a8ba-8ebdda5b5521%2Fc21625b4-187b-4727-b8d1-2ca8baed3022%2F7x8j6c8i_processed.png&w=3840&q=75)
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