6. Which set of 1 Molar aqueous solutions has the correct pH values at 25°C? A. Water pH = 0; hydrochloric acid pH = 4; acetic acid pH = 7; ammonia solution pH = 10; sodium hydroxide solution pH = 14. B. Acetic acid pH = 0; hydrochloric acid pH = 4; water pH = 7; sodium hydroxide solution pH = 10; ammonia solution pH = 14. C. Sodium hydroxide solution pH = 0; ammonia solution pH = 4; water pH = 7; acetic acid pH = 10; hydrochloric acid pH = 14. D. Hydrochloric acid pH = 0; acetic acid pH = 4; water pH = 7; ammonia solution pH = 10; sodium hydroxide solution pH = 14.

Chemistry & Chemical Reactivity
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Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
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Chapter4: Stoichiometry: Quantitative Information About Chemical Reactions
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Help me solve question 6 plz
3.
CHEMISTRY
13.Chapter+20+First+Lecture+Assignment
T
6. Which set of 1 Molar aqueous solutions has the correct pH values at 25°C?
A. Water pH = 0; hydrochloric acid pH = 4; acetic acid pH = 7; ammonial
solution pH = 10; sodium hydroxide solution pH = 14.
B. Acetic acid pH = 0; hydrochloric acid pH = 4; water pH = 7; sodium
hydroxide solution pH = 10; ammonia solution pH = 14.
13.Chapter+20+First+Lecture+Assignment
C. Sodium hydroxide solution pH = 0; ammonia solution pH = 4; water
pH = 7; acetic acid pH = 10; hydrochloric acid pH = 14.
QF: X=-b± √(b²-4ac)
2a
pH = pK, + log ([base]/[acid])
D. Hydrochloric acid pH = 0; acetic acid pH = 4; water pH = 7; ammonia
solution pH = 10; sodium hydroxide solution pH = 14.
Kw 1x10-¹4 @ 25°C
pH = -log[H3O+]
Kw=[H₂O*][OH-] Kw=K₂Kb
14 = pH + pOH @ 25°C Kp=K.(RT)An
Transcribed Image Text:3. CHEMISTRY 13.Chapter+20+First+Lecture+Assignment T 6. Which set of 1 Molar aqueous solutions has the correct pH values at 25°C? A. Water pH = 0; hydrochloric acid pH = 4; acetic acid pH = 7; ammonial solution pH = 10; sodium hydroxide solution pH = 14. B. Acetic acid pH = 0; hydrochloric acid pH = 4; water pH = 7; sodium hydroxide solution pH = 10; ammonia solution pH = 14. 13.Chapter+20+First+Lecture+Assignment C. Sodium hydroxide solution pH = 0; ammonia solution pH = 4; water pH = 7; acetic acid pH = 10; hydrochloric acid pH = 14. QF: X=-b± √(b²-4ac) 2a pH = pK, + log ([base]/[acid]) D. Hydrochloric acid pH = 0; acetic acid pH = 4; water pH = 7; ammonia solution pH = 10; sodium hydroxide solution pH = 14. Kw 1x10-¹4 @ 25°C pH = -log[H3O+] Kw=[H₂O*][OH-] Kw=K₂Kb 14 = pH + pOH @ 25°C Kp=K.(RT)An
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