5. The results of field unit weight determination of a soil sample using the sand cone method is as follows: Volume of soil: 0.00134 m³ Mass of soil: 2250 grams Dry mass of soil: 1734 grams In a laboratory, this soil yields a dry density of 1.425 g/cc at optimum moisture content of 13.8% a. What is the field unit weight of soil? b. What is the in-situ water content of soil? c. Determine the relative compaction of the soil.

5. The results of field unit weight determination of a soil sample using the sand cone method is as follows: Volume of soil: 0.00134 m³ Mass of soil: 2250 grams Dry mass of soil: 1734 grams In a laboratory, this soil yields a dry density of 1.425 g/cc at optimum moisture content of 13.8% a. What is the field unit weight of soil? b. What is the in-situ water content of soil? c. Determine the relative compaction of the soil.

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.7P

See similar textbooks

Similar questions

Let us assume that a soil sample taken in the field is taken and it must be identified by the SUCS Method and AASHTO Method. Moisture content = 5.75% Limit liquid = 53.5 Plastic limit = 31.6 Granulometry Sieve % Pass No. 4 100 # 40 68 # 200 54.3 Do you select the best answer? a) Inorganic silt and sand, with low plasticity b) Inorganic clay with low plasticity c) Clay silt, traces of gravel, dark Brown
The coefficient of permeability for a fine-grained soil is determined in a laboratory by use of a falling-head test. Test conditions and results are as indicated below. Determine the coefficient of permeability, then indicate the probable soil classification. Length of soil sample = 150 mm Cross-sectional area of sample = 1,140 mm2 Cross-sectional area of standpipe = 200 mm2 At the start of the test, the water level in the supply standpipe is 1 m above the top of the permeameter. One hour after start, the water level in the supply standpipe is 0.95 m above the top of the permeameter.
7. The results of field unit weight determination of a soil sample using the sand cone method is as follows: Volume of soil: 0.001338 m³ Mass of soil: 2300 grams Dry mass of soil: 1910 grams In a laboratory, the soil yields a dry density of 1.495 g/cc at optimum moisture content of 20.8%. Specification requires that the compacted unit weight of the soil to be at least 95 % ± 2 %of the maximum laboratory value. a. What is the field unit weight of the soil in kN/m³? b. What is the in-situ water content of soil? c. What is the relative compaction of the soil, and did it comply with the specification? Yes or no.
(b) Classification tests for the determination of the particle size distribution of a soil produced the following results: Particle Size % finer (mm) 99 2.36 80 1.3 63 0.6 33 0.2 10 0.075 3 0.02 Then using cone penetrometer for Liquid Limit test, the results were recorded as follows. Cone penetration 15.9 17.7 19.1 20.3 22.5 (mm) Water 32.6 42.9 51.6 59.8 66.2 content (%) While the plastic limit test conducted for the same soil recorded as below:- Test No. 1 2 3 Wet soil 10.01 11.23 9.72 Dry soil 8.02 9.01 7.72 SKAA 1713 4 i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b). Calculate the uniformity coefficient, Cu and the coefficient of gradation, C, for the soil sample. Determine the plastic limit, the liquid limit and the plasticity index of the soil. Plot the graph to help you obtain the results (if necessary). ii) iii)
Refer to the soil in Problem 4.5. Using the Casagrande plasticity chart, graphically estimate the shrinkage limit of the soil as shown in Figure 4.22. 4.5 The following data were obtained by conducting liquid limit and plastic limit tests on a soil collected from the site. Liquid limit tests: Plastic limit test: PL = 19.3% a. Draw the flow curve and determine the liquid limit. b. Using the Casagrande plasticity chart (Figure 4.21), determine the soil type.
Q5: Determine the soil particle density of the total soil sample based on the data given in Table 3A, Table 3B and Table 3C. Assume that the fine fraction of the total sample was 70% and the coarse fraction of the total sample was 30%. Table 3A: Data from density bottle tests Sample number Temperature (°C) Density bottle number Mass of empty bottle, m. (g) Mass of bottle + dry soil, m₂ (g) Mass of bottle + soil + water, m3 (g) Mass of bottle + water, m. (g) The apparent density of the fine fraction (g/cm³) (PC 3.5, 4.2, RS 6, RK 36) Table 3B: Data from weighing in water tests Sample number Temperature in °C Mass of dry soil particles, ms (g) Equivalent mass of wire basket immersed in water, m, (g) Equivalent mass of wire basket and soil particles immersed in water, m, (g) The soil particle density of coarse fraction (g/cm³) °C 15 16 17 892 22 18 19 Table 3C: Variation of density of water with temperature (AS 1289.3.5.1 - 2006) Density of water (P) at various temperatures g/cm³ °℃ 23 20…
Initial data for determining the specific gravity of a soil sample is given below: Calibration of Pycnometer (1) Mass of dry clean pycnometer, M₁ = 317.11 g (2) Mass of pycnometer + water at calibration temperature, Mpw,c = 903.03 g (3) Observed temperature of water at calibration, Tc = 26.4°C Secondary data for the determination of Specific Gravity is as follows: Determination No: Mass of pycnometer + soil + water at test temperature, Mpws,t (9) Test Temperature, T₁ (°C) Mass of pycnometer + water at T₁, Mpw,t (9) Evaporating dish no. Mass of evaporating dish, Md (9) Mass of evaporating dish + oven-dried soil, Mds (g) Mass of solids, Ms (9) 1 966.17 22.3 1 15.52 115.51 Conversion factor, K Specific gravity of soil, Gs@20°C Determine the Mass of Solids, Ms. (Units of g, 2 decimal places)
The size characteristics of the soil particles are shown in the table below. Classify soil using: 1. USDA Method 2. AASHTO Method (Including group index) 3. USCS Method (Full Soil Name not Symbol only) Size (mm) Percent finer 4.7500 93 2.0000 77 0.0330 69 0.0180 55 0.0100 42 0.0062 33 0.0018 24 0.0010 12 From consistency limit test, the following results are determined: Liquid Limit 32% Plastic Limit 24%
A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify the soil by both the AASHTO system and the Unified Soil classification system. Plastic Limit = 27% Mechanical grain-size analysis: Total Mass of Sample is 300 g Sieve No. 4 10 40 200 Casagrande Liquid Limit Test No of Blows 33 27 22 15 Mass Passed Through (g) 290 240 180 30 Moisture Content 18.2% 21.4% 26.6% 31.5%
The same soil sample has a natural moisture content of 30% and was subject to the Atterberg Limits test. The plastic limit was measured as 27 while the liquid limit test shows the results in the table below. Number of Blows 42 26 10 Moisture Content 20 32 45 a. Determine the liquid limit of the soil sample. Show and briefly explain how you got the answer. b. Solve and describe the Plasticity Index of the soil sample. c. Determine value and soil state of the liquidity index of the soil sample. d. Determined and describe the clay activity of the soil sample.
Initial data for determining the specific gravity of a soil sample is given below: Calibration of Pycnometer (1) Mass of dry clean pycnometer, Mp= 317.11 g (2) Mass of pycnometer + water at calibration temperature, Mpw,c = 903.03 g (3) Observed temperature of water at calibration, T = 26.4°C Secondary data for the determination of Specific Gravity is as follows: Determination No: Mass of pycnometer + soil + water at test temperature, Mpws,t (9) Test Temperature, T₁ (°C) Mass of pycnometer + water at T₁, Mpw,t (9) Evaporating dish no. Mass of evaporating dish, M. (g) Mass of evaporating dish + oven-dried soil, Mas (9) Mass of solids, M, (g) Conversion factor, K Specific gravity of soil, Gs@20°C Determine the conversion factor, K (5 decimal places) 1 966.17 22.3 1 15.52 115.51
Initial data for determining the specific gravity of a soil sample is given below: Calibration of Pycnometer (1) Mass of dry clean pycnometer, Mp= 317.11 g (2) Mass of pycnometer + water at calibration temperature, Mpw,c = 903.03 g (3) Observed temperature of water at calibration, T = 26.4°C Secondary data for the determination of Specific Gravity is as follows: Determination No: Mass of pycnometer + soil + water at test temperature, Mpws,t (9) Test Temperature, T₁ (°C) Mass of pycnometer + water at T₁, Mpw,t (g) Evaporating dish no. Mass of evaporating dish, Md (g) Mass of evaporating dish + oven-dried soil, Mds (9) Mass of solids, Mş (9) Conversion factor, K Specific gravity of soil, Gs@20°C 1 966.17 22.3 1 15.52 115.51 Determine the Mass of pycnometer + water at T₁, Mpw,t. (Units of g, 2 decimal places) Note: Find Pw,t using table 6-1.