39. The figure below shows the TCP Congestion Window for various transmission rounds of a connection. 20 18 16 14 12 10 6 2 4 8 10 12 14 16 18 20 Transmission Round 2. 00 Congestion Window (MSS)
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- Consider a TCP connection with congestion window size 40 KB, maximum segment size is 2 KB, if time taken by TCP connection to get 37 KB congestion window is 351 ms, round trip time of the connection is __(ms).An HTTP client opens a TCP connection using an initial sequence number (ISN) of 14,534 and the ephemeral port number of 59,100. The server opens the connection with an ISN of 21,732. Show the three TCP segments during the connection establishment if the client defines the rwnd of 4000 and the server defines the rwnd of 5000. Ignore the calculation of the checksum field.TCP congestion control example. Consider the figure below, where a TCP sender sends 8 TCP segments at t = 1, 2, 3, 4, 5, 6, 7, 8. Suppose the initial value of the sequence number is 0 and every segment sent to the receiver each contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at t = 6. The ACKs sent by the receiver at t = 6, 7, 8, 10, 11, 12 are shown. The TCP segments (if any) sent by the sender at t = 11, 13, 15, 16, 17, 18 are not shown. The segment sent at t=4 is lost, as is the ACK segment sent at t=7. TCP sender t=1 T t=2 t=3 t=4+ t=5- t=6+ t=11 t=12 t=13 t=14 t=15 t=16 t=17 t=18 I data segment data segment data segment data segment data segment data segment data segment data segment ACK ACK ACK ACK ACK ACK Ty A A V V htt TCP receiver t=6 t=7 t=8 t=9 t=10 t=11 t=12 t=13 What does the sender do at t=17? You can assume for this question that no timeouts have occurred.
- TCP congestion control example. Consider the figure below, where a TCP sender sends 8 TCP segments at t = 1, 2, 3, 4, 5, 6, 7, 8. Suppose the initial value of the sequence number is 0 and every segment sent to the receiver each contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at t = 6. The ACKS sent by the receiver at t = 6, 7, 8, 10, 11, 12 are shown. The TCP segments (if any) sent by the sender att = 11, 13, 15, 16, 17, 18 are not shown. The segment sent at t=4 is lost, as is the ACK segment sent at t=7. t=1 T data segment t=2+ data segment data segment-- t=3 TCP sender TCP receiver t=4+ t=5+ data segment - data segment t=6+ t36 data segment t=7 data segment t=8 data segment t=9 ACK + t=10 k -- ACK t=11 t=11 t=12 t=12 t=13 t=13 t=14 ACK -ACK ACK t=15 t=16 t=17 ACK t=18 What does the sender do at t=17? You can assume for this question that no timeouts have occurred.The filed “window size” in TCP header is in length of 16 bit. It allows 64KB as the maximal size for a TCP segment by default. Under some circumstances, the sending rate is pretty high and it results in a very short sending time (<2ms). But the end to end transmission delay is 50ms. Therefore the idle rate of a channel will be more than 2/3 . How does TCP solve this problem?Consider the figure below in which a TCP sender and receiver communicate over a connection in which the segments can be lost. The TCP sender wants to send a total of 10 segments to the receiver and sends an initial window of 5 segments at t = 1, 2, 3, 4, and 5, respectively. Suppose the initial value of the sequence number is 151 and every segment sent to the receiver each contains 612 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t = 8, and an ACK for this segment arrives at t = 15. As shown in the figure, 1 of the 5 segments is lost between the sender and the receiver, but none of the ACKs are lost. Assume there are no timeouts and any out of order segments received are thrown out.
- Question 4: Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 4 segments. Suppose the initial value of the sender->receiver sequence number is 191 and the first 4 segments each contain 250 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 0 of the 4 segment(s) are lost between the segment and receiver. TCP sender t=1 1=2 t=3 t=4 TCP segment TCP segment TCP segment TCP segment TCP receiver t-B t=9 t=10 t=11 a) Give the sequence numbers associated with each of the 4 segments sent by the sender. Format your answer as mentioned below Sequenc number for segment 1= 191 Sequenc number for segment 2= Sequenc number for segment 3= Sequenc number for segment 4- ACK number for segment 1= ACK number for segment 2= ACK number for segment 3= ACK number for segment…Consider the figure below in which a TCP sender and receiver communicate over a connection in which the sender->receiver segments may be lost. The TCP sender sends an initial window of 5 segments. Suppose the initial value of the sender->receiver sequence number is 362 and the first 5 segments each contain 638 bytes. The delay between the sender and receiver is 7 time units, and so the first segment arrives at the receiver at t=8. As shown in the figure below, 3 of the 5 segment(s) are lost between the segment and receiver.A TCP connection is using a window size of 8,000 bytes and the previousacknowledgment number was 10,001. It receives a segment with acknowledgment number 12,001 and window size advertisement of 7,000 bytes. Draw a diagram to show the situation of the window before and after.
- In TCP Fast Retransmit, if we receive three duplicate ACKS after sending out a packet that is not incrementally ACK-ed but before the time-out associated with that packet, we immediately retransmit the packet without waiting for the timeout to occur. Why do we wait for three duplicates instead of just one?Consider a long-lived TCP session with an end- to-end bandwidth 500 Mb/s. The session starts with a sequence number of 3465. The minimum time (in seconds) before this sequence number can be used again isSuppose an extension of TCP allows window size much larger than 64 KB. Assume the extended TCP runs over a 100-Mbps link with RTT 100 ms, segment size is 1 KB, and receiving window size is 1 MB. How long does it take to send a 200 KB file?