- 31x_{1} - 121x_{2} + 2.2x_{3} = - 2 - 6.1x_{1} + 5x_{2} + 11x_{3} = x_{3} = - 4.1 - 7.4x_{1} - 3.3x_{2} + - 2.1x_{3} = - 6.5 Find the value of the second component of the solution vector in format long after solving the given system by using LU factorization method on MATLAB. Your answer: O -0.212079485075284 O 0.212069485075284 O 0.227423093964027 O None. O 0.908410919381619.
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- В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }Python Activity (see pic about class Vector3D): Code for copy: class Vector3D: def __init__(self, x, y, z): # def __add__(self, other): # return None def __neg__(self): # return None def __sub__(self, other): # return None def __mul__(self, other): # return None def main(): testcases = int(input()) for t in range(testcases): line_in = input().split() op = line_in[0].strip() vec_vals = [int(x) for x in line_in[1:]] # TODO: a Write routine that processes a line in the input # op - string # - operation to do with the provided vectors # - can only be one from the set: {add, sub, neg, mul_s, mul} # vec_vals - list of integers # - numbers that follow the op in the input line # - can only have a length of 3, 4, or 6 if __name__ == '__main__': main()<?php $marks = array( "Sara" => array( "Programming" => 95, "DataBase" => 85, "Web" => 74, ), "Diana" => array( "Programming" => 78, "DataBase" => 98, "Web" => 66, ), "Amy" => array( "Programming" => 88, "DataBase" => 76, "Web" => 99, ), ); // 1 : sort the array by the name of student from A-Z; // 2 : search if Ram is exist :// if exiset print the value; else : student does not exist
- class Vector3D:def __init__(self, x, y, z):# TODO: Create a routine that saves the vector# <x, y, z> into this Vector3D object.passdef __add__(self, other):# TODO: Create a routine that adds this vector with Vector3D other# and returns the result as a Vector3D objectreturn None def __neg__(self):# TODO: Create a routine that returns the negative (opposite) of# this vector as a Vector3D object return None def __sub__(self, other):# TODO: Create a routine that subtracts this vector with Vector3D other# and returns the result as a Vector3D objectreturn None def __mul__(self, other):# TODO: Create a routine that multiplies this vector with other# depending on its data type, and returns the result as a# Vector3D object. other can either be an integer# scalar or a Vector3D object. return None def main():testcases = int(input()) for t in range(testcases):line_in = input().split()op = line_in[0].strip()vec_vals = [int(x) for x in line_in[1:]] # TODO: a Write routine that processes a line…Instructions: In the code editor, you are provided with a treasureChestMagic() function which has the following description: Return type - void Name - treasureChestMagic Parameters - an address of an integer Description - updates the value of a certain integer randomly You do not have to worry about how the treasureChestMagic() function works. All you have to do is ask the user for an integer and then call the treasureChestMagic() function, passing the address of that integer you just asked. Finally, print the updated value of the integer inputted by the user. Please create a main code for my function that works with this. This is my code: #include<stdio.h>#include<math.h> void treasureChestMagic(int*); int main(void) { // TODO: Write your code here return 0;} void treasureChestMagic(int *n) { int temp = *n; int temp2 = temp; *n = *n + 5 - 5 * 5 / 5; temp2 = (int) pow(2, 3); if(temp % 3 == 0) { *n = temp * 10; } else if(temp %…Stream : JAVA Tech Module :1 Project:1 Given the following table containing information about employees of an organization, develop a small java application, which accepts employee id from the command prompt and displays the following details as output: Emp No Emp Name Department Designation and Salary You may assume that the array is initialized with the following details: Emp Emp Join Date Desig Dept Basic HRA IT No. Name Code 1001 Ashish 01/04/2009 e R&D 20000 8000 3000 1002 Sushma 23/08/2012 PM 30000 12000 9000 1003 Rahul 12/11/2008 k Аcct 10000 8000 1000 1004 Chahat 29/01/2013 r Front 12000 6000 2000 Desk 1005 Ranjan 16/07/2005 m Engg 50000 20000 20000 1006 Suman 1/1/2000 e Manu 23000 9000 4400 factur ing 1007 Tanmay 12/06/2006 PM 29000 12000 10000 Salary is calculated as Basic+HRA+DA-IT. (DA details are given in the Designation table) Designation details : Designation Code Designation DA e Engineer 20000 C Consultant 32000 k Clerk 12000 r Receptionist 15000
- <?php $marks = array( "Sara" => array( "Programming" => 95, "DataBase" => 85, "Web" => 74, ), "Diana" => array( "Programming" => 78, "DataBase" => 98, "Web" => 66, ), "Amy" => array( "Programming" => 88, "DataBase" => 76, "Web" => 99, ), ); ?> 1 : sort the array by the name of student from A-Z; 2 : search if Ram is exist : if exiset print the value; else : student does not exist 3 : calculate the avg of each student and print it as : the avg for Sara is : 84.66Python Data = { "logs": [ { "logType": “xxxxx” }, { "logType": “43435” }, { "logType": “count” }, { "logType": “4452” }, { "logType": “count” }, { "logType": “count” }, { "logType": “43435” }, { "logType": "count" }, { "logType": "count" } ] } So, please count the total of "logType": “count” My desired output: { "count”: 5 }Functions with 2D Arrays in Java Write a function named displayElements that takes a two-dimensional array, the size of its rows and columns, then prints every element of a two-dimensional array. Separate every row by a new line and every column by a space. In the main function, call the displayElements function and pass in the required parameters. Output 1 2 3 4 5 6 7 8 9
- Kindly refer to the images for the instructions (Python language)Code Template: class Vector3D: def __init__(self, x, y, z): # TODO: Create a routine that saves the vector # <x, y, z> into this Vector3D object. pass def __add__(self, other): # TODO: Create a routine that adds this vector with Vector3D other # and returns the result as a Vector3D object return None def __neg__(self): # TODO: Create a routine that returns the negative (opposite) of # this vector as a Vector3D object return None def __sub__(self, other): # TODO: Create a routine that subtracts this vector with Vector3D other # and returns the result as a Vector3D object return None def __mul__(self, other): # TODO: Create a routine that multiplies this vector with other # depending on its data type, and returns the result as a #…// TODOd: define a "board" member variable (private) as a 2D char array of BOARD_SIZE x BOARD_SIZE // initialize it with BLANKs var board =Array( BOARD_SIZE, { Array( BOARD_SIZE, { BLANK } )A = {1,2,3} B = {1,2,3} C = {5,6,7} D = {0,1,2,3,4,5} Is A = C?