3 Ni(NO3)2•6H2O (s) + 2 Na3PO4 (aq) --> Ni3(PO4)2 (s) + 6 NaNO3 (aq) If 5.226 g Ni(NO3)2•6H2O is allowed to react with 25.00 ml of 0.1000 M Na3PO4 . How many grams of Ni3(PO4)2 can form? Start by giving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it? Select one: a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2 c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 d. None of these e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2 g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2 h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2 If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni3(PO4)2 will form? Select one: a. 0.3379 g b. 2.192 g c. 0.4575 g d. 2.650 g e. None of these f. 6.577 g g. 13.25 g h. 7.492 g i. 0.9150 g j. 1.325 g k. 3.746 g If all of the sodium phosphate reacts, that is 25.00 ml of 0.1000 M Na3PO4. How many grams of Ni3(PO4)2 can form? Select one: a. 0.4575 g b. 3.746 g c. 1.325 g d. 2.192 g e. 13.25 g f. 6.577 g g. 0.9150 g h. 2.650 g i. None of these j. 7.492 g k. 0.3379 g Using your answers from questions 2 and 3, if 5.226 g nickel (II) nitrate hexahydrate are permitted to react with 25.00 ml of 0.1000 M Na3PO4, what is the theoretical yield of Ni3(PO4)2? Select one: a. 2.650 g b. 0.4575 g c. 1.325 g d. 0.9150 g e. 2.192 g f. None of these g. 7.492 g h. 3.746 g i. 6.577 g j. 0.3379 g k. 13.25 g In the reaction of 5.226 g Ni(NO3)2•6H2O with 25.00 ml of 0.1000 M Na3PO4 , what is the limiting reagent? 3 Ni(NO3)2•6H2O (s) + 2 Na3PO4 (aq) --> Ni3(PO4)2 (s) + 6 NaNO3 (aq) Select one: a. Na3PO4 b. Ni(NO3)2•6H2O c. Ni3(PO4)2 d. None of these e. NaNO3

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Chapter20: Environmental Chemistry-earth's Environment, Energy, And Sustainability

Section: Chapter Questions

Problem 42IL

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3 Ni(NO₃)₂•6H₂O (s) + 2 Na₃PO₄ (aq) --> Ni₃(PO₄)₂ (s) + 6 NaNO₃ (aq)

If 5.226 g Ni(NO₃)₂•6H₂O is allowed to react with 25.00 ml of 0.1000 M Na₃PO₄ . How many grams of Ni₃(PO₄)₂ can form? Start by giving the mole to mole ratio for converting from moles of nickel (II) nitrate hexahydrate to moles of nickel (II) phosphate. What is it?

Select one:

a. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2•6H2O

b. 1 mol Ni(NO3)2 / 1 mol Ni3(PO4)2

c. 1 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2

d. None of these

e. 1 mol Ni3(PO4)2 / 1 mol Ni(NO3)2•6H2O

f. 1 mol Ni3(PO4)2 / 3 mol Ni(NO3)2

g. 3 mol Ni(NO3)2•6H2O / 1 mol Ni3(PO4)2

h. 1 mol Ni(NO3)2•6H2O / 3 mol Ni3(PO4)2

If all of the nickel (II) nitrate hexahydrate (5.226 g) react how many grams of Ni₃(PO₄)₂ will form?

Select one:

a. 0.3379 g

b. 2.192 g

c. 0.4575 g

d. 2.650 g

e. None of these

f. 6.577 g

g. 13.25 g

h. 7.492 g

i. 0.9150 g

j. 1.325 g

k. 3.746 g

If all of the sodium phosphate reacts, that is 25.00 ml of 0.1000 M Na₃PO₄. How many grams of Ni₃(PO₄)₂can form?

Select one:

a. 0.4575 g

b. 3.746 g

c. 1.325 g

d. 2.192 g

e. 13.25 g

f. 6.577 g

g. 0.9150 g

h. 2.650 g

i. None of these

j. 7.492 g

k. 0.3379 g

Using your answers from questions 2 and 3, if 5.226 g nickel (II) nitrate hexahydrate are permitted to react with 25.00 ml of 0.1000 M Na₃PO₄, what is the theoretical yield of Ni₃(PO₄)₂?

Select one:

a. 2.650 g

b. 0.4575 g

c. 1.325 g

d. 0.9150 g

e. 2.192 g

f. None of these

g. 7.492 g

h. 3.746 g

i. 6.577 g

j. 0.3379 g

k. 13.25 g

In the reaction of 5.226 g Ni(NO₃)₂•6H₂O with 25.00 ml of 0.1000 M Na₃PO₄ , what is the limiting reagent?

3 Ni(NO₃)₂•6H₂O (s) + 2 Na₃PO₄ (aq) --> Ni₃(PO₄)₂ (s) + 6 NaNO₃ (aq)

Select one:

a. Na₃PO₄

b. Ni(NO₃)₂•6H₂O

c. Ni₃(PO₄)₂

d. None of these

e. NaNO₃

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