3) into a 1.000 liter volumetric flask, and suddenly realize that you don't have all the reagents you expected to have. Looking around, yêu find a large carboy of 1.00 M Na2CO3. How much of this Na2CO3 solution should you add to your volumetric flask such that when it is diluted with water to the 1 liter calibration mark, the pH is 6.00 ? You may treat sulfuric acid as if it has completely dissociated (acting as a "strong acid"). Suppose you wanted to make a pH=6.0 buffer. You pipette 50 ml of 1.00 M H2SO4

3) into a 1.000 liter volumetric flask, and suddenly realize that you don't have all the reagents you expected to have. Looking around, yêu find a large carboy of 1.00 M Na2CO3. How much of this Na2CO3 solution should you add to your volumetric flask such that when it is diluted with water to the 1 liter calibration mark, the pH is 6.00 ? You may treat sulfuric acid as if it has completely dissociated (acting as a "strong acid"). Suppose you wanted to make a pH=6.0 buffer. You pipette 50 ml of 1.00 M H2SO4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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i got a answer for the a) is it correct the the pH need to be in pH 1 in order to dissolve both compound in which in acidic solution or charge ion where if it set 4 unit away from pka both compound it will be in acidic solution ? carbonyll will ( 4.8-4=0.8) and amine will (10.7-4=6.7) and different between 2 will be in 5.9 hence if pH =1 so amine will still in acidic rigth? . but for b) it state oposite which origin carbonyl in water while the origin amine in diethyl ether . and the question want the carbonyl in diethyl ether while amin ine water . so what should it do ? is it the pH still 2 unit away like ( pH around 6.8-8.7) how does it work that way ? it still at origin right ?
Ethanoic acid is a weak acid pka value 4.74 at 298K. Calculate the pH value at 298K of: a 0.1M solution of ethanoic acid. a mixture of equal volumes of 0.1M solution of ethanoic acid and sodium ethanoate.