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21. For the following equilibrium: H2C=CH2 (g) + H2 (g) €→ C2H6 (g) AH° = -136 kJ Employing Le Châtelier's Principle, qualitatively predict whether formation of C;Hs increases, decreases, or remains unchanged when this equilibrium is subjected to the following: a. Hz is removed from the system b. The reaction temperature is increased c. An effective catalyst is introduced d. The volume of the system is reduced by half

21. For the following equilibrium: H2C=CH2 (g) + H2 (g) €→ C2H6 (g) AH° = -136 kJ Employing Le Châtelier's Principle, qualitatively predict whether formation of C;Hs increases, decreases, or remains unchanged when this equilibrium is subjected to the following: a. Hz is removed from the system b. The reaction temperature is increased c. An effective catalyst is introduced d. The volume of the system is reduced by half

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.45PAE: The following equilibrium is established in a closed container: C(s)+O2(g)CO2(g)H=393kJmol1 How does...
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21. For the following equilibrium: H2C=CH2 (g) + H2 (g) E→ C2H6 (g) AH° = -136 kJ Employing Le Châtelier's Principle, qualitatively predict whether formation of C;Hs increases, decreases, or remains unchanged when this equilibrium is subjected to the following: a. Hz is removed from the system b. The reaction temperature is increased c. An effective catalyst is introduced d. The volume of the system is reduced by half
Transcribed Image Text:21. For the following equilibrium: H2C=CH2 (g) + H2 (g) E→ C2H6 (g) AH° = -136 kJ Employing Le Châtelier's Principle, qualitatively predict whether formation of C;Hs increases, decreases, or remains unchanged when this equilibrium is subjected to the following: a. Hz is removed from the system b. The reaction temperature is increased c. An effective catalyst is introduced d. The volume of the system is reduced by half
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