2. A new insecticidelaboratory test, theimmediately after contact.Is this sufficient evidence to support the advertised claim? Use α=0.05.(d) Conclusion for the problem above isis advertised to kill more than 95% roaches upon contact. In ainsecticide was applied to 400 roaches and 384 diedReject the null hypothesis and new insecticide does not kill more than 95% ofroaches upon contact.Do not reject the null hypothesis and new insecticide kills more than 95% ofroaches upon contact.Do not reject the null hypothesis and new insecticide does not kill more than95% of roaches upon contact.Reject the null hypothesis and new insecticide kills more than 95% of roachesupon contact.

An advertised new insecticide kill more than 95% roaches on contact. Population proportion p=0.95…

Answered: 2. A new insecticide laboratory test,…

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter13: Probability And Calculus

Section13.2: Expected Value And Variance Of Continuous Random Variables

Problem 10E

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Regulations from the Environmental Protection Agency say that soil used in play areas should not have lead levels that exceed a 400 parts per million (ppm). Before beginning construction at a new site, an agent will take a sample of soil and run a significance test on the mean lead level in the soil. If the mean lead level in the sample is significantly higher than 400 ppm, then the soil is deemed unsafe and construction cannot continue. Here are the hypotheses for this test: Ho : µ 400 ppm (soil is unsafe) (where u is the mean lead level in the soil at the new site). Which of the following would be a Type I error in this setting? Choose 1 answer: The soil is actually safe, and the sample result is below 400 ppm. so construction continues. The soil is actually safe, and the sample result is significantly higher than 400 ppm. so construction stops. The soil is actually unsafe, and the sample result is below 400 ppm, so construction continues. The soil is actually unsafe, and the sample…
The Department of Transportation in South Africa conducted a study a number of years ago thatshowed that the proportion of cars tested which failed to meet the state pollution standard was37%. The department would like to be able to say that the cars have improved since then. In asample of 100 cars more recently, the proportion not meeting the standards was 28%.Are the cars better at meeting the standards than they used to be? Clearly state the null andalternative hypotheses. Perform the hypothesis test at 99% confidence level and explain themeaning of your conclusion.
9% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 306 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.10? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer > = < ≠ (please enter a decimal) H1: ? p μ Select an answer > ≠ = < (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there…
Regulations from the Environmental Protection Agency say that soil used in play areas should not have lead levels that exceed a 400 parts per million (ppm). Before beginning construction at a new site, an agent will take a sample of soil and run a significance test on the mean lead level in the soil. If the mean lead level in the sample is significantly higher than 400 ppm, then the soil is deemed unsafe and construction cannot continue. Here are the hypotheses for this test: Ho : µ 400 ppm (soil is unsafe) (where u is the mean lead level in the soil at the new site). Which of the following would be a Type I error in this setting?
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? ≠ 15H0: ? = 15Ha: ? > 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? < 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject…
13% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 311 people from the inner city surveyed, 47 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer < ≠ > = (please enter a decimal) H1: ? p μ Select an answer ≠ < = > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ..
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 111, x = 12.4, and s = 6.69. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? > 15H0: ? = 15Ha: ? < 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? ≠ 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject the null…
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15% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 322 people from the inner city surveyed, 42 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be:   Ho: ? p μ  Select an answer > < = ≠   (please enter a decimal)    H1: ? μ p  Select an answer ≠ > = <   (Please enter a decimal) The test statistic ? t z  =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is ? > ≤  αα Based on this, we should Select an answer reject accept fail to reject  the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 15% at αα = 0.01, so…
10% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 369 people from the inner city surveyed, 22 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be:   Ho: ? μ p Select an answer = < ≠ > (please enter a decimal)    H1: ? μ p Select an answer > ≠ < = (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 10% at αα = 0.01, so…

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