#2-14. Normal Strain in rods constrained by walls with misfit At its initial temperature, the bar is too long by a distance of 8 to fit into the gap between the rigid walls, which are separated by distance L. In order to make it fit tightly, the bar is cooled to a very low temperature so that it shrinks enough to fit easily into th gap. After it is fit in the gap, the temperature of the bar is raised to a temperature AT below the initial temperature and the bar tight between the walls. What is the stress o in the bar at this temperature AT'? The bar has elastic modulus E = 35 10³ ksi, thermal expansion coefficient a = 6.10-6/°F and cross-sectional area A = 1 in². Use L 10 in, 8 = 3. 10-2 in and AT = -200 °F. L L

#2-14. Normal Strain in rods constrained by walls with misfit At its initial temperature, the bar is too long by a distance of 8 to fit into the gap between the rigid walls, which are separated by distance L. In order to make it fit tightly, the bar is cooled to a very low temperature so that it shrinks enough to fit easily into th gap. After it is fit in the gap, the temperature of the bar is raised to a temperature AT below the initial temperature and the bar tight between the walls. What is the stress o in the bar at this temperature AT'? The bar has elastic modulus E = 35 10³ ksi, thermal expansion coefficient a = 6.10-6/°F and cross-sectional area A = 1 in². Use L 10 in, 8 = 3. 10-2 in and AT = -200 °F. L L

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter6: Introduction To Mechanical Properties

Section: Chapter Questions

Problem 36CQ

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