1870 g of wet soil compacted into a mold with a volume of 1000 cm3. The soil is put into the oven and dried to a constant mass of 1678 kg. Gs=2.66 Define: a) water content (w) b) dry unit wight c) porosity d) degree of saturation aturated unit weight

1870 g of wet soil compacted into a mold with a volume of 1000 cm3. The soil is put into the oven and dried to a constant mass of 1678 kg. Gs=2.66 Define: a) water content (w) b) dry unit wight c) porosity d) degree of saturation aturated unit weight

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Weight-Volume relationships

Weight is defined as the quantity of matter contained in a body. Weight can also be defined as the force acting on a body due to gravity. Mathematically, weight can be defined as-

Question

1870 g of wet soil compacted into a mold with a volume of 1000 cm3. The
soil is put into the oven and dried to a constant mass of 1678 kg. Gs=2.66
Define: a) water content (w)
b) dry unit wight
c) porosity
d) degree of saturation
e) saturated unit weight

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The weight of a soil and its container is 8N. After oven-drying, the weight reduced to 6.8N. If weight of the container is IN and the volume of the soil is 402.2 cm³, determine the: a. water content b. void ratio c. bulk unit weight (kN/m³) d. saturated unit weight (kN/m³) e. effective unit weight (kN/m³) f. dry unit weight (kN/m³) g. percentage air voids h. degree of saturation
Compute the water content, void ratio, total unit weight, and dry unit weight. Weight of saturated soil in a water content container = 60g Weight after dried in air = 50g Gs = 2.7 Volume Weight Air Wa Vy Vw watci ww V. Vs solids Ws Phase diagram
The soil sample in natural state having a volume of 0.0012 cu.m. weighs 1.73 kg. The degree of saturation being 45.6%. After drying in an oven the final weight of sample was 1.44 kg. Determine the Specific Gravity.
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