13' 5' 13' + A represents spliceosome introns and B represents Group II introns A represents Group II introns and B represents Group I introns A represents Group I introns and B represents spliceosome introns A represents Group I introns and B represents Group II introns
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- Answer the following whether it is TRUE or FALSE: 1. For each DNA segment 3'-ACCTGCCTACCCG-5' the sequence of the mRNA molecule synthesized is 5'-TGGACGGATGGGC-3' 2. In the template strand TACCGAGGTATGTAC, the coding strand is 5'-ATGGCTCCATACATG-3'. 3. In the template strand TACCGAGGTATGTAC, the coding strand is 5'-AUGGCUCCAUACAUG-3'. 4. The template strand is the strand of DNA used for RNA synthesis. 5. Transcription forms a messenger RNA molecule with a sequence that is identical to the DNA template from which it is prepared.For each of the following items, fill in either the DNA strand, the MRNA codons, the tRNA anticodons, or the amino acid sequence that have been left blank. If several sequences might work, choose only one. Furthermore, circle the start and the stop codons of each mRNA sequence. 1. DNA (3'-5') ACG TAC GGC CGG TTA AAG CAT ACT TTC TTG MRNA TRNA Amino Acid 2. DNA (3'-5') MRNA AUG ACU AGC UGG GGG UAU UAC UUU UAG AAA TRNA Amino Acid 3. DNA (3'-5') MRNA TRNA GCU CCU UAC CAC ССС CGU AUG GCU GGG AUC Activate Go to Sett Amino AcidGiven the following genomic sequence which contains 2 exons and CDNA sequence predidt the amino acid sequence of the exons which are part of the coding region of a protein. How many nucleotides make up the intron? Second letter UAU TV UACJ UAA Stop|UGA Stop A UAG Stop UG Trp UUU1 Phe UUCJ UGU1, UGCJ UCU) Cys UCC Ser UCA ULA UCG CUUT CUC CUA CUG CCU CAUT C4C His CAAT CAGJ OGU CCC Leu CA CGC FArg CGA Gln CGG Pro CCG AUU AUC lle AUA ACU AGU AAU AACJ AAA 1 AAGYS Asn Ser ACC Thr ACA AGC. AGA Arg AUG Mer ACG, AGG GCU GAUT GACJ GGU GGC GUU Asp GUC Val GUA Gly Ala GAA Glu GAGJ GGA GGG GUG GCG G. Genomic antisense sequence: 5'-TAACTGATTCTAGGCTACTCTTTCACCTAA-3" CDNA sequence: 5'-TAACTGATTTCTTTCACCTAA-3" I Use the editor to format your answer First letter 皇 Third letter
- The following segment of DNA codes a protein. The uppercase letters represent Exons, the lowercase letters introns. Draw the pre- mRNA, the mature mRNA and translate the codons using the genetic code to form the protein. Identify the 5’UTR and 3UTR 5’- AGGAAATGAAATGCCAgaattgccggatgacGGTCAGCaatcgaGCACATTTGTGATTTACCGT-3’The DNA sequence below is transcribed from left to right (the partner/coding strand is shown). Using this sequence, write the sequence of the polypeptide that results from this gene. Be sure to appropriately label the ends of the molecule. 5'-ATGCACGGCGACTAG-3' Second letter A UAU Tyr UAC First letter U A G U UUU1 UUC UUA LOU Leu CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu AUU AUC lle AUA AUG Met Val C UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala CAU His CAC CAA CAG Gin AAU Asn AAC AAA 1 Lys AAG LYS G {}a UAA Stop UGA Stop A UAG Stop UGG Trp GAU 1 GAC Asp GAA GIU Glu GAGJ UGU UGC CGU CGC CGA CGG AGU AGC AGA AGG Cys GGU GGC GGA GGG Arg Ser Arg DOA DOA DOA DUTO Third letter GlyGiven the following DNA sequence: 3'-TACTTNGTNCTNTCN-5' where N stands for any nucleotide, give the complementary mRNA sequence. Indicate direction of strand as 3'--> 5' or 5'--> 3' as in the given sequence above. Give the amino acid sequence of your mRNA sequencelin No. 1. Indicate direction of strand as above. Use all lowercase letters, 3-letter name of amino acid separated by a hyphen (-), no spaces in-between.
- You may wish to consult the genetic code above to answer the following question. A mutation has changed a portion of a protein coding gene that encodes a messenger RNA sequence. The original messenger RNA sequence is 5'-AUGCCCAGAGCU-3' Which mutation is a frameshift mutation that changes all of the amino acids that follow the changed sequence? O 5-AUGCCCUGAGCU-3' 05-AUGCCCCAGAGCU-3" 05-AUGCCCACAGCU-3" 05 AUGCCCAGGGCC-3"If DNA segments changes from GCATAG to GCATA, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base U A G 0001 Phenylalanine UCU UAU1 Tyrosine (Tyr) UAC UGUT FCcysteine (Cys) UGCJ U UUCJ (Phe) UCC Serine (Ser) UCA U UUA1 UAAT UGA - Stop A FLeucine (Leu) UUG- FStop UAG- UCG- UGG - Tryptophan (Trp) G CU- CCU CGUT CAU1 Histidine (His) CAC U CUC FLeucine (Leu) CUA CC Proline (Pro) CCA CGC FArginine (Arg) CGA CAA1 Glutamine A CAGI (Glu) CGG- CUG- CCG- G AUU AAU1 Asparagine ACU1 AGUT FSerine (Ser) AGC- AUC FIsoleucine (le) ACC Threonir AACJ (Asn) A AUA- ACA (Thr) AAA1 FLysine (Lys) AAG- AGA, FArginine (Arg) AGG- A Start Methionine (Met) ACG- AUG - GUU- GCU GAU- GGU | Aspartic Acid GAÇJ(Asp) U GỤC Valine (Val) GUA GCC FAlanine (Ala) GGC Glycine (Gly) GGA G GAA1 Glutamic Acid A GCA GCG- GAGJ (Glu) GGG- GUG- GUsing the table of genetic code, choose the CORRECT protein sequence that will be produced from the following sense strand of DNA: 5'-AUG UCU GAC UAG TTG GAT CCC - 3' Second position First position (5' end) Third position (3' end) Phe Ser Tyr Cys U Phe Ser Тут Cys Leu Ser Stop Stop A. Leu Ser Stop Trp Leu Pro His Arg Leu Pro His Arg Leu Pro Gln Arg Leu Pro Gln Arg Ile Thr Asn Ser U Ile Thr Asn Ser Ile Thr Lys Arg A Met Thr Lys Arg Val Ala Asp Gly U Val Ala Asp Gly C Val Ala Glu Gly A Val Ala Glu Gly O a. Lys-His-Ala-Gly-Asn-Leu-Val O b. Val-Val-Ser-Pro-Leu-Asp-Thr
- If DNA segments changes from GCATAG to GCATGG, this is a: MRNA Codon/Amino Acid Chart First Base Second Base Third Base A G UUU1 Phenylalanine UCUT UAUT FTyrosine (Tyr) UAC UGU, U FCysteine (Cys) UGCJ UUCJ (Phe) UCC Serine (Ser) UCA U UGA - Stop A UUA1 FLeucine (Leu) UUG- UAA1 FStop UAGJ UCG- UGG - Tryptophan (Trp) G CUU CAU1 CCU1 CGUT Histidine (His) CAC- CUC CCC Proline (Pro) CCA CGC FLeucine (Leu) CUA FArginine (Arg) CGA CAA1 Glutamine A CAGJ (Glu) CGG- CUG- CCG- ACU AAUJ Asparagine AUUT AGUT FSerine (Ser) AGC- U AUC FIsoleucine (lle) ACC AACJ(Asn) Threonine A AUA- (Thr) AAA1 FLysine (Lys) AAG- АСА AGA, FArginine (Arg) AGG- A Start Methionine AUG- (Met) ACG- G GUU GCU, GAU1 Aspartic Acid GGU U GAÇJ(Asp) GUC Fvaline (Val) GUA GCC GGC G Alanine (Ala) GCA Glycine (Gly) A GAAJ Glutamic Acid GGA GAG- (Glu) GUG- GCG- GGG- GFigure 15.16 Many antibiotics inhibit bacterial protein synthesis. For example, tetracycline blocks the A site on the bacterial ribosome, and chloramphenicol blocks peptidyl transfer. What specific effect would you expect each of these antibiotics to have on protein synthesis? Tetracycline would directly affect: tRNA binding to the ribosome ribosome assembly growth of the protein chain Chloramphenicol would directly affect tRNA binding to the ribosome ribosome assembly growth of the protein chainFigure 28.41 gives some examples of recombination in IgG codons 95 and 96, as specified by the Vkand Jkgenes. List the codon possibilities and the amino acids encoded if recombination occurred in codon 97. Which of these possibilities is less desirable?
